Answer:
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Step-by-step explanation:
Given
Volume of a box = length × breadth × height= l×b×h
In this case the box have a square base. i.e l=b
Volume V = l^2 × h
The surface area of a square box
S = 2(lb+lh+bh)
S = 2(l^2 + lh + lh) since l=b
S = 2(l^2 + 2lh)
Given that the box is open top.
S = l^2 + 4lh
And Surface Area of the box is 1200cm^2
1200 = l^2 + 4lh ....1
Making h the subject of formula
h = (1200 - l^2)/4l .....2
Volume is given as
V = l^2 × h
V = l^2 ×(1200 - l^2)/4l
V = (1200l - l^3)/4
the maximum point is at dV/dl = 0
dV/dl = (1200 - 3l^2)/4
dV/dl = (1200 - 3l^2)/4 = 0
3l^2= 1200
l^2 = 1200/3 = 400
l = √400
I = 20cm
Since,
h = (1200 - l^2)/4l
h = (1200 - 20^2)/4×20
h = (800)/80
h = 10cm
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Answer:
x = 21
Step-by-step explanation:
Based on the inscribed angle theorem, we would have:
120° = 2(3x - 3)°
Solve for x
120 = 2*3x - 2*3
120 = 6x - 6
Add 6 to both sides
120 + 6 = 6x
126 = 6x
Divide both sides by 6
126/6 = x
21 = x
x = 21
Answer:
Choice A
Step-by-step explanation:
- SSS is not applicable as only 2 sides are congruent
- HL is lot applicable as triangles are not right angled (∠A and ∠E >90)
- ASA also not applicable as the angle should be included but is not
Answer:
x= 1
/3
y+
−5
/3
y=3x+5
Step-by-step explanation:
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