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scoundrel [369]
3 years ago
13

Can anyone explain how to expand and simplify 3(2a+5) +5 (a-2)

Mathematics
2 answers:
german3 years ago
8 0
First of all you need to expand this expression. you do this by multiplying the number outside the brackets with each term inside the brackets. this is the first one ;   3 x 2a = 6a, 3 x 5 = 15. the extra + sign in the first brackets stays between the two terms, so the first set of brackets is now 6a + 15. now we have to look at the second ; 5 x a = 5a, 5 x 2 = 10, like the extra + sign, the extra - sign stays between the two terms as well, so the second bracket is now 5a-10. you put them together to get  6a + 15 + 5a - 10.

next you need to simplify the expression. first you need to group like terms,        e.g. the numbers and the letters.   <u>6a</u> + <em>15 </em><u>+5a</u> <em>-</em><em>10.</em> the 6a + 5a = <em><u>11a</u></em> and the 15 - 10 = <u><em>+</em></u><em><u>5</u></em>. you then put these two terms together to get your final answer of <em><u>
</u></em>

<u><em>11a + 5</em></u>


Step2247 [10]3 years ago
5 0
Take the first bracket and it's multiplication, 3(2a+5)
You expand my multiplying everything inside the bracket by the number outside.
3*2a = 6a
3*5 = 15
Then multiply out the second bracket, 5(a-2)
5*a = 5a
5*-2 = -10
So now you have 6a + 15 + 5a - 10
Simplify it by collecting like terms, and you have:
11a + 5
And that's the answer, hope I helped!
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7 0
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NO LINKS!!!! Find the equation of the circle below​
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Answer:

(x+3)^2+(y-2)^2=9

Step-by-step explanation:

<u>Equation of a circle</u>

(x-a)^2+(y-b)^2=r^2

where:

  • (a, b) is the center
  • r is the radius

From inspection of the diagram, the center of the circle <em>appears</em> to be at point (-3, 2), although this is not very clear.  Therefore, a = -3  and  b = 2.

Substitute these values into the general form of the equation of a circle:

\implies (x-(-3))^2+(y-2)^2=r^2

\implies (x+3)^2+(y-2)^2=r^2

Again, from inspection of the diagram, the <u>maximum vertical point</u> of the circle appears to be at y = 5.  Therefore, to calculate the radius, subtract the y-value of the center point from the y-value of the maximum vertical point:

⇒ radius (r) = 5 - 2 = 3

Substitute the found value of r into the equation:

\implies (x+3)^2+(y-2)^2=3^2

Therefore, the final equation of the given circle is:

\implies (x+3)^2+(y-2)^2=9

7 0
2 years ago
Read 2 more answers
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