Answer:
AKPOS/ACGF = 28√3 -48 ≈ 0.497423
Step-by-step explanation:
Let's assume the square is a unit square. Then the height of the triangle is ...
1 +(√3)/2 = h
and half the base of the triangle is ...
h/√3 = (√3)/3 +1/2 = b/2
The area of the triangle is the product of these:
A = (1/2)bh
= (2 +√3)/2 × (3 +2√3)/6
= (6 +3√3 +4√3 +6)/12 = (12 +7√3)/12
So, the ratio of the area of the square to that of the triangle is the inverse of this, or ...
(square area)/(triangle area) = 12/(12+7√3)
(square area)/(triangle area) = 28√3 -48
Step-by-step explanation:
a^2 + 2(b - 6) - 17. a = -7 b = 2
= (-7)^2 - 2(2 - 6) - 17
= 49 - 4 + 12 - 17
= 40
The answer should be. 5x=-12
Answer:
9/1 x 3/1
Step-by-step explanation:
Answer:
<h2>
∠PZQ = 63°</h2>
Step-by-step explanation:
If point P is the interior of ∠OZQ , then the mathematical operation is true;
∠OZP + ∠PZQ = ∠OZQ
Given parameters
∠OZQ = 125°
∠OZP = 62°
Required
∠PZQ
TO get ∠PZQ, we will substitute the given parameters into the expression above as shown
∠OZP + ∠PZQ = ∠OZQ
62° + ∠PZQ = 125°
subtract 62° from both sides
62° + ∠PZQ - 62° = 125° - 62°
∠PZQ = 125° - 62°
∠PZQ = 63°
<em>Hence the value of ∠PZQ is 63°</em>
