Answer:
21 N
Step-by-step explanation:
let mass be m and weight be w
Given w varies directly with m then the equation relating them is
w = km ← k is the constant of variation
To find k use the condition m = 7 , w = 49 , then
49 = 7k ( divide both sides by 7 )
7 = k
w = 7m ← equation of variation
When m = 3 , then
w = 7 × 3 = 21 N
The word can be represented as a set and in the roaster form the set of letters is {s, a, l, t}
<h3>What is set?</h3>
A set is a collection of clearly - defined unique items. The term "well-defined" applies to a property that makes it simple to establish whether an entity actually belongs to a set. The term 'unique' denotes that all the objects in a set must be different.
We have given letter:
"salt"
Here, no letter is repeated.
So we can write it as roaster form:
Let's denote the set as S
S = {s, a, l, t}
Number of element in the set = 4
We can make new set from it if the set has only vowels
S(v) = {a}
If set has only consonants:
S(c) = {a, l, t}
Thus, the word can be represented as a set and in the roaster form the set of letters is {s, a, l, t}
Learn more about the set here:
brainly.com/question/8053622
#SPJ1
Answer:
(20 + 60) + (3 + 7) + (0.4 + 0.3) + (0.05 + 0.01)
Answers:
CB = 14
GF = 8
FB = 9
EF is parallel to CB
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Explanations:
Points E and F are midpoints of their respective sides. They form the midsegment EF. Because EF is a midsegment, A midsegment is half the length of its parallel counterpart, so CB is two times longer than EF. If EF is 7 units long, then CB = 2*EF = 2*7 = 14
For similar reasons, GF is parallel to AC. If AC = 16, then half of that is GF = (1/2)*AC = 0.5*16 = 8.
FB = FA = 9 as these segments have the same single tickmark to indicate they are the same length
EF is parallel to CB because EF is a midsegment, and this is one of the properties of being a midsegment. We can show that quadrilateral EGBF is a parallelogram to help prove this.
