You can use the direction vector as the coefficients of x and y for a line through (0, 0) perpendicular to that direction: x + y = 0. (A common factor of 4 can be removed from the coefficients.)
Translating the line up 2 and right 9, so it goes through the given point, we get ...
... (x -9) +(y -2) = 0
or
... x + y = 11
B^2+5b-24
Using the AC method for factoring
(b+8)(b-3)
Answer:
Step-by-step explanation:
<u><em>Distance between two points:</em></u> Distance between two pints 
is given by
Distance between 
Answer:
The coefficient is 3, the number right before the variable.
Given
s=16t^2
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release
Here we're given
s=144 feet
=>
s=144=16t^2
=>
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.
