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rjkz [21]
3 years ago
10

Gaseous methane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If of water is produced fro

m the reaction of of methane and of oxygen gas, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.
Chemistry
1 answer:
Nonamiya [84]3 years ago
3 0

Answer:The masses of the reactants and products formed are not included in the question, so we cannot determine the percentage yield of water without knowing the yields of other substances.

However the formulae for percentage yield is;

Percentage yield=experimental yield/theoretical yield X 100

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The immediate source of energy that powers a cell’s activities is
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<span>1. The correct option is ADENOSINE TRIPHOSPHATE, ATP. ATP is the basic unit of energy transfer in the living cells. ATP is the principal energy source for metabolic functions, in the cells, ATP are consumed by endothermic metabolic reactions and they are produced by exothermic metabolic reactions.

2. To form ATP, A THIRD PHOSPHATE GROUP HAS TO BE ADDED TO ADP. ADP has two phosphate groups while ATP has three phosphate group. ADP is usulally converted to ATP by the addition of a single phosphate group.

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5 0
3 years ago
A binary compound created by reaction of nitrogen and an unknown element E contains 30.46% N and 69.54% E by mass. If the formul
aleksklad [387]

Answer:

15.95

Explanation:

This question is a modification of the calculation of  the empirical formula of a compound given its percent composition and atomic weights of the elements in the compound.

Here we are given the formula and the percent composition, so we know that there are 4 atoms of E per 2 atoms of N so lets solve using the information given.

In 100 grams of the binary compound we have

30.46 g N

69.54 g E

The number of moles is the mass divided by atomic weight:

mol N = 30.46 g / A.W N = 30.46 g / 14.00 g/mol = 2.18 mol N

mol E = 65.54 g / A.W E

Thus,

4 mol E/ 2 mol N = ( 69.54 g/ A.W E ) / 2.18

2  A.E = 65.54 g / 2.18  ⇒ A.W E = 69.54 g / ( 2 x 2.18 ) = 15.94 g

So the A.W is 15.94 g/mol which is close  the atomic weight of O.

5 0
3 years ago
3. I bought 4 quarts of milk at the<br> store. How mariy mL is that?
dangina [55]

3785.41 milliliters

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3 years ago
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What happens to the density of the air in the balloon as it is heated?
dexar [7]
Hope it helped you.

7 0
3 years ago
A 0.288 g sample of an unknown monoprotic acid is dissolved in water and titrated with a 0.115 M NaOH solution. After the additi
Sholpan [36]

Answer:

74.0 g/mol

Explanation:

Step 1: Write the generic neutralization reaction

HA + NaOH ⇒ NaA + H₂O

Step 2: Calculate the reacting moles of NaOH

At the equivalence point, 33.83 mL of 0.115 M NaOH react.

0.03383 L × 0.115 mol/L = 3.89 × 10⁻³ mol

Step 3: Calculate the moles of HA that completely react with 3.89 × 10⁻³ moles of NaOH

The molar ratio of HA to NaOH is 1:1. The reacting moles of HA is 1/1 × 3.89 × 10⁻³ mol = 3.89 × 10⁻³ mol.

Step 4: Calculate the molar mass of the acid

3.89 × 10⁻³ moles of HA have a mass of 0.288 g.

M = 0.288 g / 3.89 × 10⁻³ mol = 74.0 g/mol

4 0
3 years ago
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