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strojnjashka [21]
3 years ago
14

Propane reacts with elemental oxygen gas according to the unbalanced reaction, C3H8(g) + O2(g) → CO2(g) + H2O(l). What is the co

efficient of the water, H2O(l), in the balanced reaction?
a
2
b
4
c
6
d
8
Chemistry
1 answer:
Ghella [55]3 years ago
8 0

Answer:

b. 4

Explanation:

The reaction expression is given as:

   C₃H₈   +   O₂     →    CO₂   +  H₂O

To solve this problem, we employ a mathematical approach.

Now use coefficient a, b, c and d as the numbers that will balance the expression:

            aC₃H₈   +   bO₂     →    cCO₂   +  dH₂O

Conserving C: 3a  = c  

                   H:  8a  = 2d

                    O: 2b  = 2c + d

let a  = 1, c  = 3, d  = 4 , b  = 5

 The balanced reaction expression is:

            C₃H₈   +   5O₂     →    3CO₂   +  4H₂O

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If 125 grams of Cu reacts 75 grams of HNO3, how many grams of Cu(NO3) form?
melisa1 [442]

Answer: 37.5grams of Cu(NO3)2

Cu(1mol) + 2HNO3(2mol) —> Cu(NO3)2 + H2

<em>125 grams of Cu(1mol) reacts with 75 grams of HNO3(2mol)</em>

<em><u>HNO3 is the limiting substance, therefore, 75 grams is the limiting quantity.</u></em>

<em>Therefore, 2mol of HNO3 forms 1mol of Cu(NO3)2</em>

<em>75 grams of HNO3 forms...75grams x 1mol/2mol = 37.5 grams of Cu(NO3)2</em>

3 0
3 years ago
A partir de lo propuesto por Bohr en 1913, que postulado es correcto:
TEA [102]

Answer:

Primer postulado:

Así Bohr asumió que el átomo de hidrógeno puede existir solo en ciertos estados discretos, los cuales son denominados estados estacionarios del átomo. En el átomo no hay emisión de radiación electromagnética mientras el electrón no cambia de órbita.

Explanation:

4 0
3 years ago
When 2.69 g 2.69 g of a nonelectrolyte solute is dissolved in water to make 345 mL 345 mL of solution at 26 °C, 26 °C, the solut
Gre4nikov [31]

Answer:

The molar concentration of this solution is 0.0463 mol/L

Explanation:

Step 1 : Data given

Mass of a nonelectrolyte solute = 2.69 grams

Volume of water = 345 mL = 0.345 L

Temperature = 26.0°CC = 273 + 26 = 299 K

The osmotic pressure = 863 torr

⇒ 863torr /760 = 1.13553 atm

Step 2: Calculate the molar concentration of this solution

Π = i*M*R*T

⇒with Π = the osmotic pressure = 1.13553 atm

⇒with i = the van't Hoff factor of the nonelectrolyte solute = 1

⇒with M = the molar concentration = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 299 K

1.13553 atm = 1 * M * 0.08206 L*atm/mol*K * 299 K

M = 1.13553 / (0.08206*299)

M = 0.0463 mol/L

The molar concentration of this solution is 0.0463 mol/L

5 0
3 years ago
For the reaction 2NH3(g) + 2O2(g)N2O(g) + 3H2O(l) H° = -683.1 kJ and S° = -365.6 J/K The standard free energy change for the rea
BlackZzzverrR [31]

Answer:

\Delta G^{0} = -457.9 kJ and reaction is product favored.

Explanation:

The given reaction is associated with 2 moles of NH_{3}

Standard free energy change of the reaction (\Delta G^{0}) is given as:

           \Delta G^{0}=\Delta H^{0}-T\Delta S^{0}   , where T represents temperature in kelvin scale

So, \Delta G^{0}=(-683.1\times 10^{3})J-(273K\times -365.6J/K)=-583291.2J

So, for the reaction of 1.57 moles of NH_{3}, \Delta G^{0}=(\frac{1.57}{2})\times -583291.2J=-457883.592J=-457.9kJ

As, \Delta G^{0} is negative therefore reaction is product favored under standard condition.

6 0
3 years ago
Having done the experiment, explain briefly how the mass of zinc not equal the mass of lead gained (hint: the periodic table)
masya89 [10]

Answer:

Due to the difference in the relative atomic masses and therefore, the molecular masses of Zn and Pb, one mole of Zn is about 3.2 times lighter than one mole of Pb

Explanation:

From the periodic table, we have;

The atomic number of zinc, Zn = 30

The atomic mass of zinc, Zn = 65.38 amu

The molar mass of zinc, Zn = 65.38 g/mol

The atomic number of lead, Pb = 82

The atomic mass of lead, Pb = 207.2 amu

The molar mass of lead, Pb = 207.2 g/mol

Therefore, whereby equal number of moles of Zn is lost and Pb is gained, we have;

Mass of 1 mole of Zn = 65.38 grams

Therefore, 1 gram of Zn = 1/65.38 moles = 0.0153 moles

0.12 grams of Zn = 0.12×0.0153 = 0.00184 moles of Zn

Given that equal number of moles of Zn and Pb are involved in the reaction, the number of moles of Pb gained = 0.00184 moles

The mass of Pb gained = Number of moles of Pb gained × Molar mass of Pb

The mass of Pb gained = 0.00184 × 207.2 = 0.38 g ≈ 0.4 g.

Amount of Pb gained = 0.43 g ≈ 0.4 g

4 0
3 years ago
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