Molarity can be defined as the number of moles of substance dissolved in 1 L of solution.
In the given question ,
number of LiOH moles - 1.495 mol
Dissolved volume - 750 mL
molarity is calculated for 1 L = 1000 mL
In 750 mL - 1.495 mol of LiOH is dissolved
Therefore in 1000 mL - 1.495 mol / 750 mL x 1000 = 1.99 mol
Answer:
dG will be the same -20 kcal/mol
Explanation:
The dG can be expressed in terms of the G(products) - G(reactants). If the amount of enzyme is doubled the Gibbs energy of the reactants and products will be the same, so the substraction dG has the same value
Answer:
Take the measuring cylinder and measure its mass, in grams, as accurately as possible.
Take the measuring cylinder off the balance and add the water carefully. Put the measuring cylinder back on the balance. Measure and record the new mass .
Repeat the procedure, recording the volume and total mass, until the measuring cylinder is full. Then, for each volume calculate the mass of the liquid alone.Repeat steps 1 to 3 Draw a graph of mass of liquid against volume . Calculate the density of each liquid from the gradient of its graph line.
Explanation:
Answer:
Explanation:
Gold (111) Chloride:
AuCl₃
The oxidation state of gold is +3.
Chlorine is present in group seventeen and have seven valance electrons . Thus it accept one electron to complete the octet and show oxidation state -1.
When it react with gold(III) three chlorine atoms are combine with one gold atom to make compound overall neutral.
Calcium Carbonate:
CaCO₃
Carbonate formula is CO₃²⁻ . It means it carry -2 charge . Calcium is present in group two. It has two valance electrons and lose them to get complete octet thus shows +2 oxidation state.
When it combine with carbonate the overall compound is neutral because -2 and +2 charges cancel each other.
Hydrobromic Acid
HBr
Hydrogen has one electron while bromine has seven valance electrons. Bromine require one more electron to complete the octet. It react with hydrogen by sharing of one electron of hydrogen and form polar covalent compound.