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3 years ago

Which tool is used to track which organisms are carriers of a specific trait through several generations?

Physics

2 answers:

mote1985 [20]3 years ago

7 0

Answer: Pedigree chart

Explanation:

Pedigree chart is the tool which can be used to track the organisms which are the carriers of a specific trait through several generations. It is a diagram which depicts the occurrence of a particular phenotypic character among the members of the same family as the phenotypic trait is passed on from the one generation to the next generation due to sexual reproduction. It is typically used to show occurrence of a particular disease, disorder, and an observable morphological trait in a family, beginning from the history to the present condition. It is commonly used to show family history for the humans, dogs and race horses.

maw [93]3 years ago

5 0

Answer:

answer is a pedigree chart :)

Explanation:

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elena55 [62]

Answer:

I took the test, and the correct answer is not Hydrosphere and Geosphere, but instead, its actually Hydrosphere and Atmosphere

Explanation:

4 0

3 years ago

What is the speed between reflected ray and the incident ray

Korvikt [17]

Answer:

The speed is the same as long as the reflection is regular.

Explanation:

This is because in regular reflection, the angle of incidence is equal to the angle of reflection in accordance with the second law of reflection.

Since speed of light depends on the angle of the light ray it makes with the reflecting surface, the speed is the same

7 0

3 years ago

Two point charges, 3.4 μC and -2.0 μC , are placed 5.0 cm apart on the x axis. Assume that the negative charge is at the origin,

Elza [17]

The electric field is zero at x = -16.45cm

Data;

q1 = 3.4 μC
q2 = -2.0 μC
distance = 5cm

<h3>The Electric Field at point 0</h3>

As the 3μC is larger than -2.0μC and the charges are opposite sign. The electric field will be zero at the negative axis.

Let the point be at x.

For an electric field to be equal to zero;

$k(\frac{q_1}{d_1})^2 + k(\frac{q_2}{d_2})^2 = 0\\\frac{3.4}{(5-x)^2} - \frac{2}{x^2} = 0\\$

Let's solve for x using mathematical methods.

$\frac{3.4x^2 - 2(5-x)^2}{(5-x)^2x^2}= 0\\ 3.4x^2 - 2(5-x^2) = 0\\3.4x^2 - 50 - 2x^2 + 20x = 0\\1.4x^2 +20x - 50 = 0$

Solving the above quadratic equation;

$x = -16.45cm$

The electric field is zero at x = -16.45cm

Learn more on electric field at a point here;

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8 0

2 years ago

An engine absorbs 2150 J as heat from a hot reservoir and gives off 750 J as heat to a cold reservoir during each cycle. What is

Aleks [24]

Input = 2,150 J; Output = 750 J
The efficiency of the engine = Output / Input = 750 J / 2,15 J = 0.3488
Answer: 0.3488 or 34.88 %

6 0

2 years ago

An electric dipole consists of charges +2e and -2e separated by 0.82 nm. It is in an electric field of strength 3.2 x 10^6 N/C.

Zepler [3.9K]

Explanation:

It is given that,

An electric dipole consists of charges +2e and -2e separated by 0.82 nm

Charge, $q=2e=2\times 1.6\times 10^{-19}\ C=3.2\times 10^{-19}\ C$

Distance between charges, $d=0.82\ nm=0.82\times 10^{-9}\ m$

Electric field strength, $E=3.2\times 10^6\ N/C$

(a) The magnitude of the torque on the dipole is given by :

$\tau=p\times E\ sin\theta$

When dipole moment is parallel to the electric field, $\theta=0$

$\tau=p\times E\ sin(0)$

$\tau=0$

(b) When the dipole is perpendicular to the electric field, $\theta=90$

$\tau=pE\ sin(90)$

$\tau=qdE$ (Since, p = q × d)

$\tau=3.2\times 10^{-19}\times 0.82\times 10^{-9}\times 3.2\times 10^6$

$\tau=8.39\times 10^{-22}\ N.m$

(c) When the dipole moment is anti parallel to the electric field, $\theta=180$

$\tau=pE\ sin(180)$

Since, $sin\ 180=0$

$\tau=0$

Hence, this is the required solution.

8 0

3 years ago