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belka [17]
3 years ago
10

Which tool is used to track which organisms are carriers of a specific trait through several generations?

Physics
2 answers:
mote1985 [20]3 years ago
7 0

Answer: Pedigree chart

Explanation:

Pedigree chart is the tool which can be used to track the organisms which are the carriers of a specific trait through several generations. It is a diagram which depicts the occurrence of a particular phenotypic character among the members of the same family as the phenotypic trait is passed on from the one generation to the next generation due to sexual reproduction. It is typically used to show occurrence of a particular disease, disorder, and an observable morphological trait in a family, beginning from the history to the present condition. It is commonly used to show family history for the humans, dogs and race horses.

maw [93]3 years ago
5 0

Answer:

answer is a pedigree chart :)

Explanation:

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Q: Compare and contrast the different parts of the Electromagnetic Spectrum. Evaluate the usefulness of each part and decide whi
LUCKY_DIMON [66]

The infrared and ultraviolet parts of the electromagnetic spectrum can be used in the field of chemical analysis.

The sections of the EM spectrum are named in order of increasing energy gamma rays X-rays ultraviolet-visible light infrared, and radio waves. Microwaves used in microwave ovens are a subsection of the radio segment of the EM spectrum.

Electromagnetic energy travels in waves and covers a wide spectrum from very long radio waves to very short gamma rays. The human eye can only see a small portion of this spectrum known as visible light. The electromagnetic spectrum includes all frequencies of electromagnetic radiation that carry energy and travel through space in the form of waves. Low frequencies and long wavelengths make up the radio spectrum.

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3 0
1 year ago
What pressure, in millimeters of mercury (mm Hg), is equivalent to 2.13 atmospheres
Sati [7]
The "Standard Atmosphere" is 760 mm Hg . 2.13 times that pressure is (2.13 x 760) = 1,618.8 mm Hg.
6 0
3 years ago
When a plane flies with the​ wind, it can travel 1575 miles in 3.5 hours. when the plane flies in the opposite​ direction, again
Zepler [3.9K]

When plane is flying along the wind then we can say

V_{plane} + v_{wind} = \frac{distance}{time}

V_{plane} + v_{wind} = \frac{1575}{3.5}

V_{plane} + v_{wind} = 450 mph

Now when its going against the wind the speed is given by

V_{plane} - v_{wind} = \frac{distance}{time}

V_{plane} - v_{wind} = \frac{1575}{4.5}

V_{plane} - v_{wind} = 350 mph

Now by the above two equations we will have

V_{plane} = 400 mph

v_{wind} = 50 mph

3 0
3 years ago
11 kg is a familiar weight for a bag of flour. You are baking cookies for a Save The Rain Forest fund drive. It takes 500 g of f
arlik [135]

Answer: 22 batches.

Explanation:

Given that 11 kg is a familiar weight for a bag of flour. Also, it is given that It takes 500 g of flour to make one batch of cookies.

How many batches of cookies can you make with one bag of flour

Let's first convert 11 kg into grams (g) by multiplying it by 1000

11 × 1000 = 11000 g

Divide 11000 by 500

11000/500 = 22

Therefore, 22 batches of cookies can be made with one bag of flour.

8 0
3 years ago
A man jogs at a speed of 1.6 m/s. His dog waits 1.8 s and then takes off running at a speed of 3 m/s to catch the man. How far w
inessss [21]

Answer:

The dog catches up with the man 6.1714m later.

Explanation:

The first thing to take into account is the speed formula. It is v=\frac{d}{t}, where v is speed, d is distance and t is time. From this formula, we can get the distance formula by finding d, it is d=v\cdot t

Now, the distance equation for the man would be:

d_{man}=v_{man}\cdot t=1.6\cdot t

The distance equation for the dog would be obtained by the same way with just a little detail. The dog takes off running 1.8s after the man did. So, in the equation we must subtract 1.8 from t.

d_{dog}=v_{dog}\cdot (t-1.8)=3\cdot (t-1.8)

For a better understanding, at t=1.8 the dog must be in d=0. Let's verify:

d_{dog}=v_{dog}\cdot (1.8-1.8)=3\cdot (0)=0

Now, for finding how far they have each traveled when the dog catches up with the man we must match the equations of each one.

d_{man}=d_{dog}

1.6\cdot t=3\cdot (t-1.8)

1.6\cdot t=3\cdot t-5.4

1.4\cdot t=5.4

t=\frac{5.4}{1.4}

t=3.8571s

The result obtained previously means that the dog catches up with the man 3.8571s after the man started running.

That value is used in the man's distance equation.

d_{man}=1.6\cdot t=1.6\cdot (3.8571)

d_{man}=6.1714m

Finally, the dog catches up with the man 6.1714m later.

6 0
3 years ago
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