So the problem ask to calculate the magnitude of the average force applied to the ball if its mass is 0.2kg changes its velocity from 20m/s to 12m/s and the time contact with the ball with the wall is 60 ms. In my calculation the best answer would be 107N.
I think answer should be d. Please give me brainlest I hope this helps let me know if it’s correct or not okay thanks I appreciate it
Given that : d = 5sin(pi t/4), So, maximum displacement, d = 5*(+1) = 5 Also, maximum displacement, d = 5*(-1) = -5
Answer:
0.24
Explanation:
Mass of ball= 12g=0.012Kg
height of ball= 2.5m
velocity of ball before falling= 3.2m/s
potential energy of the ball=mgh= 0.012*10*2.5=0.3J
kinetic energy of the ball=0.5*m
=0.5*0.012*3.2*3.2=0.6J
Loss in mechanical energy during the fall= potential energy- Kinetic energy= 0.3-0.06=0.24J
note: During the fall, the potential energy of the ball is converted to kinetic energy. the loss in energy is due to air resistance.
Answer:
<em>Reaching activation energy</em><em> is necessary because reactants require a </em><em>minimum</em><em> </em><em>amount of energy</em><em> start breaking a</em><em> chemical bond.</em>
Explanation:
Activation energy is the minimum amount of energy required by the reactants to initiate a chemical reaction. The unit of activation energy is joule or kilo joule per mole or kilo calories per mole. Activation energy depends on temperature.
The temperature dependence of activation energy is given by Arrhenious equation. Activation energy is a threshold value of energy. For any reaction to occur this is the minimum amount of energy required.
