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2 years ago

How can atoms make up all of the substances around you

1 answer:

6 0

How can atoms make up all of the substances around you? Because there are a lot of atoms in the substances. ... If atoms are made of smaller parts such as electrons,why are atoms considered the basic unit of matter? It is the smallest unit that has the chemical property's of an element.

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If a bag of pretzels says it contains 10 servings, and each serving is 150 calories, how many calories would you consume if you

Sindrei [870]

Answer:

5400

Explanation:

i calculated it

Big brain

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2 years ago

Which example below provides a complete scientific description of an object in motion?

EastWind [94]

C. The marble moved 30 cm north in 6 seconds.

This gives a scientific or correct value of object in motion among all other options.

- BRAINLIEST answerer

7 0

2 years ago

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the average time required for radioactive elements, whereby they decay to half their original mass is called the "average life"

VikaD [51]

I'm not sure what your question is. But, the half life is the amount of time required for half the material to decay. For U238 this is 4.5 billion years, whilst for Fr-223 (Francium) its about 22 minutes. To calculate the time for something to decay you need to use the equation:
Mass (after time t) = Mass (initial) * (0.5)^(time/half life)
Hope this helps

4 0

2 years ago

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The two speakers at S1 and S2 are adjusted so that the observer at O hears an intensity of 6 W/m² when either S1 or S2 is sounde

Zanzabum

Answer:

The minimum frequency is 702.22 Hz

Explanation:

The two speakers are adjusted as attached in the figure. From the given data we know that

$S_1 S_2$ =3m

$S_1 O$ =4m

By Pythagoras theorem

$S_2O=\sqrt{(S_1S_2)^2+(S_1O)^2}\\S_2O=\sqrt{(3)^2+(4)^2}\\S_2O=\sqrt{9+16}\\S_2O=\sqrt{25}\\S_2O=5m$

Now

The intensity at O when both speakers are on is given by

$I=4I_1 cos^2(\pi \frac{\delta}{\lambda})$

Here

I is the intensity at O when both speakers are on which is given as 6 $W/m^2$

I1 is the intensity of one speaker on which is 6 $W/m^2$

δ is the Path difference which is given as

$\delta=S_2O-S_1O\\\delta=5-4\\\delta=1 m$

λ is wavelength which is given as

$\lambda=\frac{v}{f}$

Here

v is the speed of sound which is 320 m/s.

f is the frequency of the sound which is to be calculated.

$16=4\times 6 \times cos^2(\pi \frac{1 \times f}{320})\\16/24= cos^2(\pi \frac{1f}{320})\\0.667= cos^2(\pi \frac{f}{320})\\cos(\pi \frac{f}{320})=\pm0.8165\\\pi \frac{f}{320}=\frac{7 \pi}{36}+2k\pi \\ \frac{f}{320}=\frac{7 }{36}+2k \\\\ {f}=320 \times (\frac{7 }{36}+2k )$