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Harman [31]
4 years ago
9

If the crate shown here is moving at a constant speed in a straight line and the force applied is 310 N, what is the magnitude o

f the force of friction?
A.310 N
B.0 N
C.620 N

Physics
1 answer:
larisa86 [58]4 years ago
8 0

Answer:

f_k = 310N

the answer is A.

Explanation:

Using the laws of newton:

∑F = ma

where ∑F is the sumatory of forces acting in the system, m the mass and a the acelertion of the system.

Then, if the block is moving with constant velocity, its aceleration is equal to 0, so:

∑F = m(0)

∑F = 0

It means that:

F -f_k = 0

where F is the force applied and f_k is the friction force. Replacing the value of F, we get:

310N -f_k = 0

Finally, solving for f_k:

f_k = 310N

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