The equation for determining the kinetic energy of the system is,
KE = 0.5mv²
where m is the mass, v is velocity and KE is the kinetic energy. When both objects have the same mass, and velocity but different direction, they will have the same kinetic energy.
This is because the exponent in the velocity is squared cancelling out the effect of the sign appearing before the number.
You haven't included the list of choices that goes with the question, so it's
impossible for me to choose the correct one, or to help you choose it.
Regarding my ability to answer the question and collect the 5-point bounty,
I'm free to make up any phrase of my own that correctly describes an atom.
-- very very very very very very very tiny
-- includes even tinier particles, with electric charges
both positive and negative
-- smaller than the wavelength of visible light
Answer:
Thrust developed = 212.3373 kN
Explanation:
Assuming the ship is stationary
<u>Determine the Thrust developed</u>
power supplied to the propeller ( Punit ) = 1900 KW
Duct distance ( diameter ; D ) = 2.6 m
first step : <em>calculate the area of the duct </em>
A = π/4 * D^2
= π/4 * ( 2.6)^2 = 5.3092 m^2
<em>next : calculate the velocity of propeller</em>
Punit = (A*v*β ) / 2 * V^2 ( assuming β = 999 kg/m^3 ) also given V1 = 0
∴V^3 = Punit * 2 / A*β
= ( 1900 * 10^3 * 2 ) / ( 5.3092 * 999 )
hence V2 = 8.9480 m/s
<em>Finally determine the thrust developed </em>
F = Punit / V2
= (1900 * 10^3) / ( 8.9480)
= 212.3373 kN
The question is missing, however, I guess the problem is asking for the value of the force acting between the two balls.
The Coulomb force between the two balls is:
where
is the Coulomb's constant,
is the intensity of the two charges, and
is the distance between them.
Substituting these numbers into the equation, we get
The force is repulsive, because the charges have same sign and so they repel each other.
