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3 years ago

Steps for Seperating mixtures flowers peteale water and sugar

Chemistry

1 answer:

Thepotemich [5.8K]3 years ago

4 0

Answer:

How can we separate sugar from the mixture of sugar and water like we can remove acetone from water? The mixture of sugar-salt solution can be separated by evaporation. If the water is completely evaporated we will get separated sugar from the mixture.

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How does a filter separate mixtures like sand and water?

Talja [164]

Answer:

Filtration is a method for separating an insoluble solid from a liquid. When a mixture of sand and water is filtered: the sand stays behind in the filter paper (it becomes the residue ) the water passes through the filter paper (it becomes the filtrate )

Explanation:

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3 years ago

What is the mass of 1.45 moles of silver sulfate?

tatuchka [14]

Answer:

449.5 g

Explanation:

Silver sulfate- Ag2SO4

M(Ag)=107 g/mol => M(Ag2)=214 g/mol

M(S)=32 g/mol

M(O)=16 g/mol => M(O4)=64 g/mol

M(Ag2SO4)=310 g/mol

n=1.45 mol

m(Ag2SO4)=M(Ag2SO4)*n=310 g/mol *1.45 mol= 449.5 g

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3 years ago

Read 2 more answers

By mistake, a quart of oil was dumped into a swimming pool that measures 25.0 m by 30.0 m. The density of the oil was 0.750 g/cm

kondor19780726 [428]

The oil slick thick = 1.256 x 10⁻⁴ cm

<h3>Further explanation</h3>

Volume is a derivative quantity derived from the length of the principal

The unit of volume can be expressed in liters or milliliters or cubic meters

The conversion is

1 cc = 1 cm3

1 dm = 1 Liter

1 L = 1.06 quart

<em>so for 1 quart = 0.943 L</em>

$\tt 0.943~L=0.943\times 10^{-3}m^3$

Volume of oil dumped = volume of swimming pool

$\tt 0.943\times 10^{-3}~m^3=25\times 30\times h(h=thick)\\\\h=\dfrac{0.943\times 10^{-3}}{750~m^2}=1.257\times 10^{-6}~m=\boxed{\bold{1.256\times 10^{-4}~cm}}$

3 0

3 years ago

How many grams of oxygen are required to burn 60 grams of ethane gas, C2H6? 2 C2H6 (g) + 7 O2(g) → 4 CO2 (g) + 6 H2O (g)

timofeeve [1]

60 g C2H6 × 1 mol C2H6 x 7 mol O2 x 32 g O2 = ~223.5 g O2
30.068 g 2 mol C2H6 1 mol O2

8 0

3 years ago

Help............???????

balandron [24]

B. .175

Hope it helps!

4 0

3 years ago