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3 years ago

Which pair of compounds represents one Arrhenius acid and one Arrhenius base?

Chemistry

2 answers:

svlad2 [7]3 years ago

5 0

Answer: 3) $HNO_3$ and $NaOH$

Explanation:

According to the Arrhenius concept, an acid is a substance that ionizes in the water to give hydronium ion or hydrogen ion.

$HNO_3\rightarrow H^++NO_3^-$

According to the Arrhenius concept, a base is a substance that ionizes in the water to give hydroxide ion.

$NaOH\rightarrow Na^++OH^-$

Thus $HNO_3$ is an arrhenius acid and $NaOH$ is an arrhenius base.

notka56 [123]3 years ago

5 0

Answer:

HNO3 AND NaOH

Explanation:

Arrhenius acids have H as the only plus ion solution and Arrhenius base contains OH negative is the only negative ions in aqueous solution

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A substance in which light can travel through such as air,glass, or water

Stels [109]

Answer:

The correct answer is - transparent medium.

Explanation:

A transparent substance or medium is the substance that allows light to pass through it. Light moves through these substances as they do not absorb the light and do not reflect too.

The example of such substances is glass, air or water. These substances allow light to pass through them.

Thus, The correct answer is - transparent medium.

6 0

3 years ago

Julie takes a cold glass of clear, colorless liquid out of the refrigerator and puts it on the table. As the liquid warms up to

marysya [2.9K]

The bubbles indicate that there is a gas dissolved in the liquid, which may remain dissolved when the liquid is very cold, inside the refrigerator.

When the temperature of the liquid increases, it reduces its ability to dissolve the gas and the gas escapes (bubbles) from the liquid.

At the end, the behavior of the liquid permits you to conclude that the liquid is a mixture because it has a gas dissolved in it.

8 0

3 years ago

Read 2 more answers

What is the empirical formula of a compound that contains 75% Ag and 25% Cl by mass

lesya [120]

Answer:

The answer to your question is AgCl

Explanation:

Data

Silver = Ag = 75%

Chlorine = Cl = 25%

1.- Convert percent numbers to grams

Silver = 75 g

Chlorine = 25 g

2.- Calculate the moles of each element

Mass number Ag = 108 g

Mass number Cl = 35.5 g

108 g of Ag ------------------ 1 mol

75 g of Ag ------------------ x

x = (75 x 1) / 108

x = 75 / 108

x = 0.69 moles

35.5 g of Cl ------------------ 1 mol

25 g of Cl ----------------- x

x = (25 x 1) / 35.5

x = 0.70 moles

3.- Divide by the lowest number of moles

Ag = 0.69/0.69 = 1

Cl = 0.70 / 0.69 = 1.02 ≈ 1

4.- Write the empirical formula

Ag₁ Cl₁ = AgCl

5 0

3 years ago

A sample of H2 gas (12.28 g) occupies 100.0 L at 400.0 K and 2.00 atm. A sample weighing 9.49 g occupies ________ L at 353 K and

lutik1710 [3]

Considering the ideal gas law, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P× V = n× R× T

In this case, you know:

P= 2 atm
V= ?
n= $9.49 gramsx\frac{1 mole}{2 grams} = 4.745moles$ being 2g/mole the molar mass of H2, that is, the amount of mass that a substance contains in one mole.
R= 0.082 $\frac{atmL}{molK}$
T= 353 K

Replacing:

2 atm× V = 4.745 moles× 0.082 $\frac{atmL}{molK}$ × 353 K

Solving:

V = (4.745 moles× 0.082 $\frac{atmL}{molK}$ × 353 K)÷ 2 atm

Finally, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.

Learn more:

brainly.com/question/4147359?referrer=searchResults

5 0

2 years ago

You find a little bit (0.150g) of a chemical marked Tri-Nitro-Toluene, and upon combusting it in oxygen, collect 0.204 g of CO2

avanturin [10]

1) Answer is: the formula is C₇N₃O₆H₅.

M(TNT) = 0.150 g; mass of the trinitrotoluene.

ω(N) = 18.5% ÷ 100%.

ω(N) = 0.185; mass percentage of the nitrogen.

m(N) = 0.150 g · 0.185.

m(N) = 0.02775 ·; mass of the nitrogen.

n(N) = 0.02775 g ÷ 14 g/mol.

n(N) = 0.002 mol; amount of the nitrogen.

n(CO₂) = 0.204 g ÷ 44 g/mol.

n(CO₂) = 0.0046 mol.

n(C) = n(CO₂) = 0.0046 mol; amount of the carbon.

m(C) = 0.0046 mol · 12 g/mol.

m(C) = 0.0552 g; mass of the carbon.

n(H₂O) = 0.030 g ÷ 18 g/mol.

n(H₂O) = 0.00166 mol.

n(H) = 2 · n(H₂O) = 0.0033 mol; amount of the hydrogen.

m(H) = 0.0033 mol · 1 g/mol.

m(H) = 0.0033 g; mass of the hydrogen.

2) m(O) = m(TNT) - m(N) - m(C) - m(H).

m(O) = 0.150 g - 0.02775 g - 0.0552 g - 0.0033 g.

m(O) = 0.06375 g.

n(O) = 0.06375 g ÷ 16 g/mol.

n(O) = 0.004 mol; amount of oxygen.

n(C) : n(N) : n(O) : n(H) = 0.0046 mol : 0.002 mol : 0.004 mol : 0.0033 mol.

n(C) : n(N) : n(O) : n(H) = 2.33 : 1 : 2 : 1.66 /×3.

n(C) : n(N) : n(O) : n(H) = 7 : 3 : 6 : 5.

8 0

3 years ago