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AnnZ [28]
3 years ago
11

Summarize the difference between legal law and scientific law

Chemistry
2 answers:
alex41 [277]3 years ago
7 0

Answer:

Legal laws are passed by lawmakers in a democratic process that accounts for people's opinions and beliefs.

Scientific laws are discovered and tested by experiments.

Legal laws can be changed if people change their minds.

Legal laws may have exceptions.

on edg

Explanation:

Gnom [1K]3 years ago
4 0
Scientific law is based on answers that are a result of experimentation, number of repetitive tests (to ensure credible results), and observations about Earth's atmosphere and it's life

Legal law is based from morale and principle high ground that are designed to bring order through an armed force. If you look at it very carefully, it's designed to control human nature, savagery, and instinctual behaviour. How so? Without order, everything morphs into chaos as people have the liberty to fight, kill, and steal without penalization.
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Can someone tell me the answer and how to do the problem?
Wittaler [7]

Answer:

is tht wht u want

Explanation:

1 grams Sodium is equal to 0.043497607849056 mole.

4 0
3 years ago
how many moles of sodium are needed to react with sulfuric acid to produce 3.75 moles of sodium sulfate according to the followi
anastassius [24]
Hello!
<span>
You'll need to react 7,5 moles of Sodium with sulfuric acid to produce 3.75 moles of sodium sulfate
</span>
First of all, you need to balance the reaction. The balanced reaction is shown below (ensuring that the Law of Conservation of Mass is met on both sides):

2Na + H₂SO₄ → Na₂SO₄ + H₂

Now, all that you have to do is to use molar equivalences in this reaction applying the coefficients to calculate the moles of Sodium that you'll need:

molesNa=3,75moles Na_{2} SO_4* \frac{2 moles Na}{1 mol Na_{2} SO_4} =7,5 moles Na 

Have a nice day!
5 0
2 years ago
Mark as brainlist asap plz <br><br><br><br><br><br> i need the answer asap
Darya [45]
A
Please mark as brainliest
Emily
5 0
3 years ago
Will give lots of points if answered correctly. Determine the kb for chloroform when 0.793 moles of solute in 0.758 kg changes t
Liono4ka [1.6K]

Answer: The value of K_{b} for chloroform is 3.62^{o}C/m when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

Explanation:

Given: Moles of solute = 0.793 mol

Mass of solvent = 0.758

\Delta T_{b} = 3.80^{o}C

As molality is the number of moles of solute present in kg of solvent. Hence, molality of given solution is calculated as follows.

Molality = \frac{no. of moles}{mass of solvent (in kg)}\\= \frac{0.793 mol}{0.758 kg}\\= 1.05 m

Now, the values of K_b is calculated as follows.

\Delta T_{b} = i\times K_{b} \times m

where,

i = Van't Hoff factor = 1 (for chloroform)

m = molality

K_{b} = molal boiling point elevation constant

Substitute the values into above formula as follows.

\Delta T_{b} = i\times K_{b} \times m\\3.80^{o}C = 1 \times K_{b} \times 1.05 m\\K_{b} = 3.62^{o}C/m

Thus, we can conclude that the value of K_{b} for chloroform is 3.62^{o}C/m when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

7 0
3 years ago
A 50.0-g sample of liquid water at 25.0 °c is mixed with 23.0 g of water at 79.0 °c. the final temperature of the water is ___
I am Lyosha [343]

<span><span>m1</span>Δ<span>T1</span>+<span>m2</span>Δ<span>T2</span>=0</span>

<span><span>m1</span><span>(<span>Tf</span>l–l<span>T<span>∘1</span></span>)</span>+<span>m2</span><span>(<span>Tf</span>l–l<span>T<span>∘2</span></span>)</span>=0</span>

<span>50.0g×<span>(<span>Tf</span>l–l25.0 °C)</span>+23.0g×<span>(<span>Tf</span>l–l57.0 °C)</span>=0</span>

<span>50.0<span>Tf</span>−1250 °C+23.0<span>Tf</span> – 1311 °C=0</span>

<span>73.0<span>Tf</span>=2561 °C</span>

<span><span>Tf</span>=<span>2561 °C73.0</span>=<span>35.1 °C</span></span>

8 0
3 years ago
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