The first thing you do is go two space forward like start at the o and move two spaces forward you put a decimal at 9 like this 0.90 and that's how you do it
Answer:
Option 2 is right
Step-by-step explanation:
Given that

We can write this in polar form with modulus and radius

Hence angle = 60 degrees and

Since we have got 5 roots for z, we can write 60, 420, 780, etc. with periods of 360
Using Demoivre theorem we get 5th root would be
5th root of 2 multiplied by 1/5 th of 60, 420, 780,....
![z= \sqrt[5]{2} (cos12+isin12)\\z=\sqrt[5]{2} (cos84+isin84)\\\\z=\sqrt[5]{2} (cos156+isin156)\\\\z=\sqrt[5]{2} (cos228+isin228)\\\\z=\sqrt[5]{2} (cos300+isin300)\\](https://tex.z-dn.net/?f=z%3D%20%5Csqrt%5B5%5D%7B2%7D%20%28cos12%2Bisin12%29%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos84%2Bisin84%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos156%2Bisin156%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos228%2Bisin228%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos300%2Bisin300%29%5C%5C)
Out of these only 2nd option suits our answer
Hence answer is Option 2.
Answer:
a = -3.8
b = -2.6
c = 1.7
d = 4.4
e = 1.0
Step-by-step explanation:
In the figure attached, the tables are shown.
In an inverse relationship, any point (x,y) in one table is transformed to (y,x) in the other one. For example, in Table A coordinate (1, 2) is present, then in Table B (the inverse), coordinate (2, 1) must be present.
So we have the equation:

Then we need to multiply by 4 on both sides to get rid of the denominator on the left:

Then we subtract 9 on both sides to solve for z:

Therefore the answer is z = -0.6.
No, the answer is 24th.
The LCM of 3 and 4 is 12.
(3,6,9,12)(4,8,12)
12th April +12=24th April