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miv72 [106K]
3 years ago
9

A scientist observes a petri dish containing a number of bacteria. On the first day, the dish had 300 bacteria on the second day

, the dish had 1200 bacteria. On the third day, the dish had 4800 bacteria. If the pattern continues how many bacteria will the dish have on the fourth day? on the nth day
Mathematics
2 answers:
dezoksy [38]3 years ago
8 0
I Think the answer is  because the pattern is to multiply it by 4



19200 answer

vivado [14]3 years ago
3 0

Answer:

19200

Step-by-step explanation:

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If f(x) = 3x^2 – 2 and g(x) = 2x + 4, find (f- g)(x).
Andreas93 [3]

Answer:

(f - g)(x) = 3x² - 2x - 6

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 3x² - 2

g(x) = 2x + 4

(f - g)(x) is f(x) - g(x)

<u>Step 2: Evaluate</u>

  1. Substitute:                    (f - g)(x) = 3x² - 2 - (2x + 4)
  2. Distribute -1:                 (f - g)(x) = 3x² - 2 - 2x - 4
  3. Combine like terms:    (f - g)(x) = 3x² - 2x - 6
5 0
3 years ago
Please can someone help me
disa [49]

Answer:

I believe your answer is correct.

Step-by-step explanation:

3 0
2 years ago
Solve for r.<br><br> r - 4.5 ≤ 11
erma4kov [3.2K]

Answer:

The answer is r < or equal to 15.5.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
What is the interquartile range of the set of data represented by the following box-and-whisker plot?
Valentin [98]
In descriptive statistics, the interquartile range<span> (</span>IQR<span>), also called the midspread or middle 50%, or technically H-spread, is a measure of statistical dispersion, being equal to the difference between 75th and 25th percentiles... ~ wikipedia

according to Wikipedia and some quick mental math the answer would be four

four is the difference between 14 and 18 which are respectively the 25th and 75th percentiles.</span><span />
7 0
3 years ago
Read 2 more answers
Suppose that 75% of all trucks undergoing a brake inspection at a certain inspection facility pass the inspection. Consider grou
RSB [31]

Answer:

b) 0.2961

c) 0.2251

d) Mean = 11.25, Standard deviation =  1.667  

Step-by-step explanation:

We are given the following information:

We treat trucks undergoing a brake inspection passin as a success.

P( trucks undergoing a brake inspection passes the test) = 75% = 0.75

a) Conditions for binomial probability distribution

  1. There are n independent trial.
  2. Each trial have a success probability p
  3. The probability of success is same for all trials.

Then the number of trucks undergoing a brake inspection follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 15

b) P(proportion of groups will between 8 and 10 trucks pass the inspection)

We have to evaluate:

P(8\leq x \leq 10) = P(x = 8) + P(x = 9) + P(x = 10)\\= \binom{15}{8}(0.75)^8(1-0.75)^7 + \binom{15}{9}(0.75)^9(1-0.75)^6 + \binom{15}{10}(0.75)^{10}(1-0.75)^5\\= 0.0393 + 0.0917 + 0.1651\\= 0.2961

c) P( exactly 3 trucks fail the inspection)

p = 0.25

P(x = 3)\\= \binom{15}{3}(0.25)^3(1-0.25)^{12}\\=0.2251

d) Mean and standard deviation

\mu = np = 15(0.75) = 11.25\\\sigma = \sqrt{np(1-p)} = \sqrt{15(0.75)(1-0.75)} = 1.667

6 0
3 years ago
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