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miv72 [106K]
3 years ago
9

A scientist observes a petri dish containing a number of bacteria. On the first day, the dish had 300 bacteria on the second day

, the dish had 1200 bacteria. On the third day, the dish had 4800 bacteria. If the pattern continues how many bacteria will the dish have on the fourth day? on the nth day
Mathematics
2 answers:
dezoksy [38]3 years ago
8 0
I Think the answer is  because the pattern is to multiply it by 4



19200 answer

vivado [14]3 years ago
3 0

Answer:

19200

Step-by-step explanation:

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What coordinates are 7 units away from (2,−7)
AlekseyPX
One coordinate that is 7 units away from (2,-7) is (2,0). (2,0) is 7 units to the right of (2,-7)

Another coordinate is (9,-7). This one also works.
7 0
3 years ago
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Match the two numbers with their least common multiple
Darya [45]

8 -<u> 8</u>, 16, 24, 32, 40, 48  

4 - 4, <u>8</u>, 12, 16,

So the LCM of 8 and 4 are C) 8

8 - 8, 16, <u>24</u>, 32, 40, 48

6 - 6, 12, 18,<u> 24</u>, 30

So the LCM of 8 and 6 are A) 24

8 - 8, 16, 24, 32, <u>40</u>, 48

10 - 10, 20, 30, <u>40</u>, 50

The LCM of 8 and 10 are B) 40

Hope this Helps!!

3 0
3 years ago
Which fraction is equivalent to 16/20 ?A.8/100 <br> B.6/10<br> C.48/60<br> D.20/24
denis23 [38]

Answer:

Step-by-step explanation:

16/20 = 48/60

960 = 960

Answer is C

3 0
3 years ago
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Heart failure is due to either natural occurrences (89%) or outside factors (11%). Outside factors are related to induced substa
Firdavs [7]

Answer:

a) 11% probability that the first patient with heart failure that enters the emergency room has the conditions due to outside factors.

b) 0.0871 = 8.71% probability that third patient with heart failure that enters the emergency room is the first one due to outside factors.

c) The mean number of heart failure patients with the condition due to natural causes that enter the emergency room before the first patient with heart failure from outside factors is 9.09.

Step-by-step explanation:

We have these following probabilities:

89% probability that a patient has heart failure due to natural occurrences.

11% probability that a patient has heart failure due to outside factors.

A) What is the probability that the first patient with heart failure that enters the emergency room has the conditions due to outside factors?

We assume that causes of heart failure between individuals are independent, which means that the probabilities are the same for each patient. So:

11% probability that the first patient with heart failure that enters the emergency room has the conditions due to outside factors.

B) What is the probability that third patient with heart failure that enters the emergency room is the first one due to outside factors?

First two due to natural occurrences, each with 89% = 0.89 probability.

Third due to outside factors, with 11% = 0.11 probability. So

0.89*0.89*0.11 = 0.0871

0.0871 = 8.71% probability that third patient with heart failure that enters the emergency room is the first one due to outside factors.

C) What is the mean number of heart failure patients with the condition due to natural causes that enter the emergency room before the first patient with heart failure from outside factors?

11% with outside factors, so the mean number of patients before the first with outside factors is given by

m = 1/0.11 = 9.09

The mean number of heart failure patients with the condition due to natural causes that enter the emergency room before the first patient with heart failure from outside factors is 9.09.

4 0
3 years ago
John is renting a car.The car cost 36 dollars each day plus $0.50 per mile over 100 miles.John rents the car for 5 days and driv
Deffense [45]

Answer:

36*5+80 =260

Step-by-step explanation:

hope this helps

6 0
3 years ago
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