Answer:
hey
Step-by-step explanation:
I like ya cut g XD
Answer:
no because for right angle triangle the sum of the sq of the two smallest side is equal to the sq of biggest side
When you look at the table, find the y value that has equivalent values on both sides. For example, the y value for the vertex here is 10. After it, the values are 7,-2, and 17, and above it, the values are 7 and -2. This value should also be either the largest y value or smallest y value (depending on whether the parabola opens up or down).
Answer: (a)- 
Step-by-step explanation:
Given
Central angle is 
The radius of the unit circle is 
Arc length is given by

Put the values

Answer:

Step-by-step explanation:
The given expression is

We need to find the simplified form of the given expression.
It can be rewritten as

Combine integers and fractions separately.

Taking LCM we get


In can be written as




Therefore, the expression
is equivalent to the given expression.