3/4[4÷(7-4)] evaluate
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Answer:
Step-by-step explanation:
Remark
Begin by omitting all the pqrs bases that are raised the 0 power. Anything to the zero power = 1.
Multiply what is left.
Solution
Group One: p^-1
Group Two: p^-1 q^-3 s^-1
Group Three: q^-1r^-2s^-1
From groups 1 and 2 p is p^-2
From groups 2 and 3 q is q^-4
From groups 3 r is r^-2
From groups 2 and 3 s is s^-2
Notice that when the powers are - when the power is in the numerator, those powers become positive when they switch to the denominator.
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