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3 years ago

3/4[4÷(7-4)] evaluate

Mathematics

1 answer:

Thepotemich [5.8K]3 years ago

6 0

I’m pretty sure this is the answer

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Which of the following is the linear parent function?A.F(x) = 2xB.F(x) = |x|C.F(x) = x2D.F(x) = x

Daniel [21]

The linear parent function is f(x)=x

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3 years ago

Pythagorean theorem a=7 and c=14. Can you explain how to find b?

nikdorinn [45]

Answer:

c squared - a squared = b squared

Step-by-step explanation:

Since a squared + b squared = c squared

With these values it would equal 14 squared - 7 squared = c squared

Then after you find c squared, find the square root of it and there you have go your answer!

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3 years ago

How much would $200 invested at 7% interest compounded annually be

raketka [301]

<h3>Answer: Choice A. $280.51</h3>

Work Shown:

A = P*(1+r/n)^(n*t) .... compound interest formula

A = 200(1+0.07/1)^(1*5) .... plug in given info

A = 200*(1.07)^5

A = 200*1.4025517307

A = 280.51034614

A = 280.51

3 0

3 years ago

HELP WILL MARK YOU BRAINLIEST NO FAKE ANSWERS

Elis [28]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The given statement can be represented as :

2b³ - b

where, the number is assumed to be " b "

therefore, the correct choice is B. 2b³ - b

7 0

2 years ago

Question regarding logarithms.

Eddi Din [679]

$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot5^{x-4}\\\\5^{x-2}-7^{x-2-1}=7^{x-2-3}+11\cdot5^{x-2-2}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\5^{x-2}-\dfrac{7^{x-2}}{7^1}=\dfrac{7^{x-2}}{7^3}+11\cdot\dfrac{5^{x-2}}{5^2}\\\\5^{x-2}-\dfrac{1}{7}\cdot7^{x-2}=\dfrac{1}{343}\cdot7^{x-2}+\dfrac{11}{25}\cdot5^{x-2}\\\\-\dfrac{1}{7}\cdot7^{x-2}-\dfrac{1}{343}\cdot7^{x-2}=\dfrac{11}{25}\cdot5^{x-2}-5^{x-2}\\\\\left(-\dfrac{1}{7}-\dfrac{1}{343}\right)\cdot7^{x-2}=\left(\dfrac{11}{25}-1\right)\cdot5^{x-2}$

$\left(-\dfrac{49}{343}-\dfrac{1}{343}\right)\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\\\\-\dfrac{50}{343}\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\qquad\text{multiply both sides by}\ \left(-\dfrac{25}{14}\right)\\\\\dfrac{50\cdot25}{343\cdot14}\cdot7^{x-2}=5^{x-2}\qquad\text{divide both sides by}\ 7^{x-2}\\\\\dfrac{25\cdot25}{343\cdot7}=\dfrac{5^{x-2}}{7^{x-2}}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}$

$\dfrac{5^2\cdot5^2}{7^3\cdot7}=\left(\dfrac{5}{7}\right)^{x-2}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{5^4}{7^4}=\left(\dfrac{5}{7}\right)^{x-2}\\\\\left(\dfrac{5}{7}\right)^4=\left(\dfrac{5}{7}\right)^{x-2}\iff x-2=4\qquad\text{add 2 to both sides}\\\\\boxed{x=6}$

6 0

3 years ago

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