How does the graph of g(x) = 3X – 2 compare to the graph of f(x) = 3X?

ollegr [7]

There will be two squares.

Think about it: The shorter side is 3.5 feet. The longer side is 7 feet. If he cuts it in half on the longer side, he's taking the length of that longer side, and dividing it by 2. 7/2=3.5.

So, you'd have two squares, both with a length and width of 3.5 feet.

5 0

3 years ago

50 points! Expert verified please help me ! Random answers will be reported

Vikentia [17]

Answer:

(1,-2)

Step-by-step explanation:

(x,y)transforms(y,-x)at about 270°.

3 0

3 years ago

graph the solutions of the inequality on a number line. Describe the solution to the inequality. p > 4

inysia [295]

Draw out a number line. Make sure 4 is on the number line. At this location, plot an open circle. The open circle indicates "do not include this endpoint as part of the solution set". We shade to the right of this open circle.

Visually this describes all real numbers that are larger than 4.

5 0

3 years ago

How to solve this math

Scorpion4ik [409]

The second choice is correct

4 0

3 years ago

Assume we cut the last piece of the pie into two sections (1 and 2) along ray BD

earnstyle [38]

Answer:

If we want the greatest portion of pie, then you must choose the section with the greatest angle. Therefore, we must choose Section 2. But if we want the smallest portion of pie, then we must choose Section 1.

Step-by-step explanation:

From statement, we know that measure of the angle ABC is equal to the sum of measures of angles ABD (<em>section 1</em>) and DBC (<em>section 2</em>), that is to say:

$m \angle ABC = m\angle ABD + m\angle DBC$ (1)

If we know that $m\angle ABC = 40^{\circ}$ , $m\angle ABD = 2\cdot x + 3$ and $m\angle DBC = 4\cdot x + 7$ , then the value of $x$ is:

$(2\cdot x + 3)+(4\cdot x + 7) = 40^{\circ}$

$6\cdot x +10^{\circ} = 40^{\circ}$

$6\cdot x = 30^{\circ}$

$x = 5$

Then, we check the angles of each section:

Section 1

$m\angle ABD = 2\cdot x + 3$

$m\angle ABD = 13^{\circ}$

Section 2

$m\angle DBC = 4\cdot x + 7$

$m\angle DBC = 27^{\circ}$

If we want the greatest portion of pie, then you must choose the section with the greatest angle. Therefore, we must choose Section 2. But if we want the smallest portion of pie, then we must choose Section 1.

6 0

3 years ago