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Alexus [3.1K]
3 years ago
5

How to find a ratio for a repeating decimal

Mathematics
1 answer:
Marta_Voda [28]3 years ago
5 0
<span>Let x equal the repeating decimal you are trying to convert to a fraction.Examine the repeating decimal to find the repeating digit(s)<span>Place the repeating digit(s) to the left of the decimal point.</span></span>
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(a) Compute two lines of regression from the following data:
Natasha_Volkova [10]

Answer:

can you write this on paper and send me? i have feeling ik this but i don't understand what u need

3 0
3 years ago
6x-5y=15 x=y+3 find x and y
arlik [135]

Answer:

(0, -3)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Coordinates (x, y)
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

6x - 5y = 15

x = y + 3

<u>Step 2: Solve for </u><em><u>y</u></em>

<em>Substitution</em>

  1. Substitute in <em>x</em>:                                                                                                  6(y + 3) - 5y = 15
  2. Distribute 6:                                                                                                    6y + 18 - 5y = 15
  3. Combine like terms:                                                                                        y + 18 = 15
  4. [Subtraction Property of Equality] Subtract 18 on both sides:                     y = -3

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Define original equation:                                                                               x = y + 3
  2. Substitute in <em>y</em>:                                                                                                   x = -3 + 3
  3. Add:                                                                                                                   x = 0
7 0
3 years ago
Data Entry - No Scoring During your procedure to determine the uncalibrated volume near the stopcock of your buret, what was the
DaniilM [7]

Answer:

0.025 grams

Step-by-step explanation:

The water in the stopcock has a volume of 25 mL initially, After that, the whole water was drained out. So we have:

Volume of drained water = (25 mL)(1 x 10⁻⁶ m³/1 mL)

Volume of drained water = 25 x 10⁻⁶ m³

Density of drained water = 1000 kg/m³

So, for the mass of drained water:

Density of drained water = Mass of drained water/Volume of drained water

Mass of drained water = (Density of drained water)(Volume of drained water)

Mass of drained water = (1000 kg/m³)(25 x 10⁻⁶ m³)

<u>Mass of drained water = 0.025 gram</u>

Density

4 0
3 years ago
GIVING BRAINIEST!!!!!!!!
Sav [38]

Answer:

look at the horizontal line in the picture. the degree measure of any line is 180° given there's a perpendicular ray through that horizontal line it's therfore split into two sides both with angle measure of 90°.

given f is 71° then g can be found knowing that both g and f must add to 90°. 71+g=90. g=19°

now look at f again. f and d are what's known as vertical angles and that means that they're angle measures are congruent. therfore the measure of d is 71° d=71°

Finally to find e we notice that angle d and e form a straight line which means both angles measures must add to 180°. therefore e can be found by computing d+e=180

aunaitituitmg our information we know 71+e=180 then e must equal 109° e=109°

3 0
3 years ago
If mBDE = 125 what is mGDF? A) 35. B) 45. C) 55. D) 65
joja [24]
A supplmentary angle = 180°

∠BDE and ∠BDF are vertical angles, and so are congruent.

∠BDF = 125°, because ∠BDF ≅ ∠BDE.

∠CDA ≅ ∠EDF

∠CDA = 90°


<span>line BJ </span> is angle bisector of ∠CDA. ∠CDB is 1/2 of ∠CDA

∠CDA = 90°

∠CDB = 90/2
∠CDB = 45°

∠GDF is a vertical angle of ∠CDB, and it's measurement will be the same as ∠CDB.

∠GDF ≅ ∠CDB
∠CDB = 45°
∠GDF  = 45°


∠GDF  = 45° should be your answer

hope this helps
7 0
3 years ago
Read 2 more answers
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