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3 years ago

Why do the air molecules inside a bicycle tire speed up as the temperature gets warmer?

2 answers:

6 0

The correct answer of the given question above would be option A. The air molecules inside a bicycle tire speed up as the temperature gets warmer because the heat is transferred to the molecules and gives them more kinetic energy. When heat is added to a substance, the molecules and atoms vibrate faster.

Mice21 [21]3 years ago

5 0

Answer: Option (a) is the correct answer.

Explanation:

When temperature of surrounding atmosphere around the tire increases then it will lead to increase in the kinetic energy of molecules.

Due to increase in kinetic energy of molecules there will be more number of collisions between the air molecules that are present inside the bicycle tire.

Hence, it means heat has been transferred from the surrounding atmosphere to the molecules inside the tire.

Thus, we can conclude that the air molecules inside a bicycle tire speed up as the temperature gets warmer because the heat is transferred to the molecules and gives them more kinetic energy.

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a particular application calls for N2 g with a density of 1.80 g/L at 32 degrees C what must be the pressure of the n2 g in mill

baherus [9]

Answer:

1223.38 mmHg

Explanation:

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

Also,

Moles = mass (m) / Molar mass (M)

Density (d) = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

$PM=dRT$

Given that:-

d = 1.80 g/L

Temperature = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (32 + 273.15) K = 305.15 K

Molar mass of nitrogen gas = 28 g/mol

Applying the equation as:

P × 28 g/mol = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K

⇒P = 1223.38 mmHg

1223.38 mmHg must be the pressure of the nitrogen gas.

5 0

3 years ago

A 15.00-mL sample of an NaOH solution of unknown concentration requires 17.88 mL of a 0.1053 M H2SO4 M solution to reach the equ

Anastasy [175]

Answer:

The concentration of the NaOH solution CB = 0.251 M

Explanation:

The balanced equation of reaction is:

H2SO4 + 2NaOH ===> Na2SO4 + 2H2O

Using titration equation of formula

CAVA/CBVB = NA/NB

Where NA is the number of mole of acid = 1 (from the balanced equation of reaction)

NB is the number of mole of base = 2 (from the balanced equation of reaction)

CA is the concentration of acid = 0.1053 M

CB is the concentration of base = to be calculated

VA is the volume of acid = 17.88 mL

VB is the volume of base = 15.00mL

Substituting

0.1053×17.88/CB×15 = 1/2

Therefore CB =0.1053×17.88×2/15×1

CB= 0.251 M

6 0

4 years ago

According to the kinetic theory, what is the kinetic energy of a gas molecule proportional to? volume of the gas pressure of the

Hatshy [7]

ANSWER: C temperature of the gas

5 0

4 years ago

Classify each process according to direction of heat flow.

GenaCL600 [577]

Answer:

heat flows in

heat flows out

heat flows put

Explanation:

8 0

3 years ago

Read 2 more answers

The balanced chemical equation for the reaction between PCl5 and water is given below. If 3.45 moles of HCl are produced, how ma

enyata [817]

The coefficients of the substances give you the ratio of the number of moles.
The 4 before the H2O and the 5 before the HCl tell you that for every 5 moles of HCl created, 4 moles of H2O had to react.

Therefore:
$(3.45mol HCl)(\frac{4 mol H2O}{5 mol HCl})$
can be used to find the moles of H2O that react.

$(3.45mol HCl)(\frac{4 mol H2O}{5 mol HCl}) = 2.76 mol H20$

6 0

3 years ago