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natulia [17]
3 years ago
6

Need help !!!!! In this question im stuck

Chemistry
1 answer:
GenaCL600 [577]3 years ago
5 0

Decrease, increase and increase I think this is correct

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1. Que factores provocan la oxidación?
Katyanochek1 [597]

Answer:

Mira la explicación.

Explanation:

Hola,

Las reacciones de oxidación se definen como aquellos procesos químicos en las cuales uno de los elementos involucrados sufre un aumento en su estado de oxidación, causado por el efecto de un agente oxidante, el cual es capaz de aceptar los electrones perdidos por dicho elemento oxidante. Dentro de los factores promotores de la oxidación se pueden encontrar:

1. Presencia de oxígeno gaseoso: al ser un agente oxidante fuerte, es capaz de recibir electrones de casi cualquier sustancia.

2. Presencia de humedad: a la larga, cuando una sustancia reacciona con agua tiende oxidarse ya que el agua posee oxígeno y como se vio anteriormente, es el principal promotor de oxidación.

3. La presencia de algunas sales iónicas como cloruro de sodio también promueven la oxidación, por ello es que no debemos introducir joyería al mar, debido a que esta salinidad induce reacciones electroquímicas que son capaces de oxidar metales.

4. Reacciones con ácidos oxidantes: ácidos como el nítrico, son oxidantes fuertes que tienen la capacidad de disolver metales (oxidarlos) y formar nitratos, por ejemplo el cobre en presencia de ácido nítrico, sufre una oxidación bastante violenta.

Saludos!

4 0
3 years ago
A chemical reaction which uses a molecule of water to break apart another molecule is most commonly called
Artyom0805 [142]

That is called hydrolysis.

4 0
3 years ago
What is a manipulated variable
ivanzaharov [21]
It is the independent variable because you can ‘manipulate’ or ‘change’ it.
6 0
3 years ago
Consider the following multistep reaction:
chubhunter [2.5K]

The question is incomplete, here is the complete question:

Consider the following multistep reaction:

C+D⇌CD (fast)

CD+D→CD₂ (slow)

CD₂+D→CD₃ (fast)

C+3D→CD₃

Based on this mechanism, determine the rate law for the overall reaction.

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k'[C][D]^2

<u>Explanation:</u>

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

C+3D\rightarrow CD_3

The intermediate reaction of the mechanism follows:

<u>Step 1:</u>  C+D\rightleftharpoons CD;\text{ (fast)}

<u>Step 2:</u>  CD+D\rightarrow CD_2;\text{(slow)}

<u>Step 3:</u>  CD_2+D\rightarrow CD_3;\text{(fast)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[CD][D]           ......(1)

As, [CD] is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for CD from step 1, we get:

K=\frac{[CD]}{[C][D]}

[CD]=K[C][D]

Putting the value of [CD] in equation 1, we get:

\text{Rate}=k.K[C][D]^2\\\\\text{Rate}=k'[C][D]^2  

Hence, the rate law for the reaction is \text{Rate}=k'[C][D]^2

5 0
3 years ago
How do you convert 42.7L to mL
zimovet [89]
1L=1000 mL,L GOES BOTTOM AND mL GOES TOP,ANSWER SHOULD BE 42700.
4 0
4 years ago
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