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2 years ago

Sulfur reacts with oxygen to produce sulfur trioxide gas. Balance the equation. S+(sub2) -----> __SO(sub3)

1 answer:

6 0

2S + 3O2 ==> 2SO3
Let's start off with the unbalanced equation and count atoms of each element on both sides of the arrow.
S + O2 ==> SO3
There's 1 sulfur atom on both sides which is good. However, there's 2 oxygen atoms on the left and 3 on the right. So calculate the Least common multiple (LCM) of 2 and 3 which is 6. And adjust the coefficients on both sides to have 6 oxygen atoms on each side, giving:
S + 3O2 ==> 2SO3
Now we have 6 oxygen atoms on each side which is good, but there's only 1 sulfur atom on the left and 2 on the right. Since the LCM of 1 and 2 is 2, all we need to do is adjust the coefficient on the left to get 2 sulfur atoms there. So:
2S + 3O2 ==> 2SO3
We now have 2 sulfur atoms on each side of the equation and 6 oxygen atoms on each side, so the resulting equation is balanced.

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$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.3556 M

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Putting values in above equation, we get:

$0.3556M=\frac{\text{Mass of iron (III) nitrate}\times 1000}{241.86 g/mol\times 129.8}\\\\\text{Mass of iron (III) nitrate}=11.16g$

Hence, the mass of iron (III) nitrate is 11.16 g/mol

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2 years ago

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Marat540 [252]

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2 years ago

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Eddi Din [679]

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2 years ago

Determine the change in volume that takes place when a 2.00 L sample of N2 gas is heated from 250 C to 500 C.

Effectus [21]

Answer:

V₂ = 2.96 L

Explanation:

Given data:

Initial volume = 2.00 L

Initial temperature = 250°C

Final volume = ?

Final temperature = 500°C

Solution:

First of all we will convert the temperature into kelvin.

250+273 = 523 k

500+273= 773 k

According to Charles's law,

V∝ T

V = KT

V₁/T₁ = V₂/T₂

V₂ = T₂V₁/T₁

V₂ = 2 L × 773 K / 523 k

V₂ = 1546 L.K / 523 k

V₂ = 2.96 L

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3 years ago

Sulfur reacts with oxygen to produce sulfur trioxide gas. Balance the equation. __S+__(sub2) -----> __SO(sub3)

Sulfur reacts with oxygen to produce sulfur trioxide gas. Balance the equation. S+(sub2) -----> __SO(sub3)