When you litter,
the trash can go into the ocean, and a fish could think of it as food, eat it, suffocate and die,
Same thing for land (but no ocean)
Here's how to do it:
<span>Balanced equation first: </span>
<span>Mg + HCl = H2 + MgCl2 unbalanced </span>
<span>Mg + 2 HCl = H2 = MgCl balanced </span>
<span>Therefore 1 mole Mg reacts with 2 moles Hcl. </span>
<span>50g Mg = ? moles (a bit over 2; you work it out) </span>
<span>75 g HCl = ? moles (also a bit over 2; you work it out) </span>
<span>BUT, you need twice the moles HCl; therefore it is the Mg that is in excess. (you can now work out how many moles are in excess, and therefore how much mg is left over). </span>
<span>So, 2 moles HCl produce 1 mole H2(g) </span>
<span>therefore, the amount of H2 produced is half the number of moles of HCl </span>
<span>At STP, there are X litres per mole of gas (look it up - about 22 from memory) </span>
<span>Therefore, knowing the moles of H2, you can calculate the volume</span>
I don't understand . Sorry :(
Here this is what happens
The formatting of the question is a bit scrambled: I'm not sure if there are separate steps that have been unintentionally consolidated into a seemingly discrete step, nor am I sure which letters actually correspond with which step(s). So, for clarity's sake, I treated every sentence as its own step and arranged all of them accordingly. Hopefully, you can then reorganize them according to the labeled steps as you have been provided.
- Suspend a separatory funnel using an iron ring and ring stand.
- Make sure the stopcock is closed.
- Transfer the organic (dichloromethane) layer to the funnel.
- Add an equivalent volume of aqueous acid to the dichloromethane layer in the separatory funnel.
- Cap the separatory funnel with a glass or Teflon stopper.
- Remove the funnel from the iron ring and shake vigorously to mix the layers, periodically venting to release pressure.
- Place the separatory funnel back in the Iron ring.
- Allow the layers to physically separate in the funnel.
- Remove the cap.
- Drain the bottom layer into a labeled beaker.
- Label the beaker "Organic Layer".
- Drain the remaining liquid into a labeled beaker.
- Label this beaker "Aqueous Layer".
- Transfer the "Organic Layer" back to the empty separatory funnel.
- Repeat all steps.
Notes:
- The letters have been replaced with numbers only to clarify the order of the steps. No changes were made to the steps themselves, including any stylistic errors.
- A <em>very few</em> set of sequential steps might be interchangeable, but the steps as separated and organized above is in accordance with standard liquid-liquid extraction protocol.
- Determining which layers are the "organic" and "aqueous" layers (i.e., whether the organic/aqueous layer, or vice-versa, is on the bottom/top ) is a nontrivial step; for this reason, when actually doing such extractions, the beakers (or whatever vessel) into which the layers are drained at any step are sometimes labeled "top layer" and "bottom layer" in case you misidentify which layers are, in fact, the organic and aqueous layers. Oftentimes, the organic layer is on top of the aqueous layer as many common organic solvents are less dense than water. Halogenated organic solvents, like dichloromethane, are one of the exceptions, and so will generally comprise the bottom layer.
