Question

Consider the function f(x) = (x − 3)2(x + 2)2(x − 1).

Answer 1

we have

$f(x)=(x-3)^{2}(x+2)^{2}(x-1)$

we know that

The zero of the function is  the value of x when the value of the function is equal to zero

$f(x)=(x-3)^{2}(x+2)^{2}(x-1)$

rewrite the function

$f(x)=(x-3)(x-3)(x+2)(x+2)(x-1)$

The zero's of the function are

$x=3\ x=3\ x=-2\ x=-2\ x=1$

so

$x=3$ ------> has a multiplicity of $2$

$x=-2$ ------> has a multiplicity of $2$

$x=1$ ------> has a multiplicity of $1$

therefore

the answer is

The zero $1$ has a multiplicity of $1$

The zero $-2$ has a multiplicity of $2$

Answer 2

The zero 1 has a multiplicity of 1.

The zero -2 has a multiplicity of 2.

Hope this clears up any confusion :)