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3 years ago

Mhanifa please help! Explain how you can use the perpendicular bisector of a segment to draw an isosceles triangle.

Mathematics

1 answer:

Anna007 [38]3 years ago

7 0

Answer:

If you construct the perpendicular bisector of a line segment, every point on the perpendicular bisector will be the same distance from both point A and point B.

To construct an isosceles triangle, you can start from any point on the perpendicular bisector and draw line segments to point A and to point B

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Trying this again for another 30 point and brainly

ki77a [65]

Answer:

Step-by-step explanation:

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3 years ago

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Please help me with these two problems

vodka [1.7K]

First pic ; they are complementary angles , so C !!

second pic ; both angles are supplementary angles !! as sum is 180° !!

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3 years ago

Help help me please!!!!!!!

Makovka662 [10]

Answer:

okay so the first question says divide :40203 by 13

= after dividing the quotient comes as 3092

Step-by-step explanation:

then to verify the answer using division algorithm

the formula is as dividend = (q x d) + remainder

so the verification= 13 x 3092 + 7 = 4023

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3 years ago

What is the area of the pool?

IRISSAK [1]

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3 years ago

Number 1 and 2 please (25 points)

Elenna [48]

Answers:

1) $(3x+2)+(4-5x)=-2x+6$

$(3+2i)+(4-5i)=7-3i$

2) $(1-3x)(2+x)=-3x^{2}-5x+2$

$(1-3i)+(2+i)=5-5i$

Step-by-step explanation:

In mathematics there are rules related to complex numbers, specifically in the case of addition and multiplication:

<u>Addition: </u>

If we have two complex numbers written in their binomial form, the sum of both will be a complex number whose real part is the sum of the real parts and whose imaginary part is the sum of the imaginary parts (similarly as the sum of two binomials).

For example, the addition of these two binomials is:

$(3x+2)+(4-5x)=3x-5x+2+4=-2x+6$

Similarly, the addition of two complex numbers is:

$(3+2i)+(4-5i)=3+4+2i-5i=7-3i$ Here the complex part is the number with the $i$

<u>Multiplication: </u>

If we have two complex numbers written in their binomial form, the multiplication of both will be the same as the multiplication (product) of two binomials, taking into account that $i^{2}=-1$ .

For example, the multiplication of these two binomials is:

$(1-3x)(2+x)=2+x-6x-3x^{2}=-3x^{2}-5x+2$

Similarly, the multiplication of two complex numbers is:

$(1-3i)+(2+i)=2+i-6i-3i^{2}=2-5i-3(-1)=5-5i$

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3 years ago