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natulia [17]
3 years ago
12

If x2 + y2 = 14 and xy=5, find the value of (½x+½y)². pls help​

Mathematics
2 answers:
dimulka [17.4K]3 years ago
7 0

Answer:

(½x+½y)²=6

Step-by-step explanation:

x^2 + y^2 = 14, xy=5

(A+B)^2=A^2 +2AB+B^2... (*)

(1/2x+1/2y)^2 =(*)

(1/2x)^2 +2(1/2x)(1/2y)+(1/2y)^2 =

1/4x^2 +1/2xy+1/4y^2=

1/4(x^2 +y^2) +1/2(xy)=

1/4*14+1/2*5=

14/4+5/2=

14/4+10/4=

24/4=6

Valentin [98]3 years ago
4 0

Answer:

Step-by-step explanation:

Given: x² + y² = 14 and xy = 5

(a + b)²  = a²  + b²  + 2ab

(\frac{1}{2}x+\frac{1}{2}y)^{2}=(\frac{1}{2}x)^{2}+(\frac{1}{2}y)^{2}+2*\frac{1}{2}x*\frac{1}{2}y\\\\=\frac{1}{4}x^{2}+\frac{1}{4}y^{2}+x*\frac{1}{2}y\\\\=\frac{1}{4}x^{2}+\frac{1}{4}y^{2}+\frac{1}{2}xy\\\\=\frac{1}{4}*(x^{2}+y^{2})+\frac{1}{2}xy\\\\=\frac{1}{4}*14+\frac{1}{2}*5\\\\=\frac{7}{2}+\frac{5}{2}\\\\=\frac{12}{2}\\\\=6

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Answer:

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Step-by-step explanation:

The formula for Confidence Interval =

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Standard deviation = $2,050

Mean = $45,420

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Confidence Interval = $45,420 ± 1.645 × $2,050/√25

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Therefore, the Confidence Interval = ($44,745.55 , $46,094.45)

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In document below




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Which statement is true about the value of |-14|​
fomenos

Answer:

14

Step-by-step explanation:

Next time, please share the possible answer choices.

The absolute value of any quantity, whether it be a + or - quantity, is zero or positive.

Thus, |-14| = the absolute value of -14 = +14

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