Answer:
5
Step-by-step explanation:
We can express 125 as 5 x 5 x 5. Therefore, the value of the cube root of 125 is 5.
![\sqrt[3]{125} = \sqrt[3]{5 \times 5 \times 5} = 5](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B125%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B5%20%5Ctimes%205%20%5Ctimes%205%7D%20%20%3D%205)
Answer:
a.) First check on the height of the bar that ranges between 20 and 24 which is 6. The 6 is the number of students who bought 20 books or more, so get the percentage of those students who bought 20 or more books; divide 6 which is the number of students who bought 20 books or more with the total number of students which is 40 then multiply with 100.
% of students who bought 20 or more books = 6/40 ×100
=15
Step-by-step explanation:
b.) Find the area of a trapezium
= 1/2 × {a+b} × h
= 1/2 × {9 + 13} ×12
= 132
= 1/2 × {13 + 6} × 12
= 108
Mean no. of books bought = 132 + 108
= 240
<span>The third side of triangle ABC is AB. Using the Pythagorean Theorem, its length is 12.
12² + 16² = 20²
∠F is congruent to ∠C and so the sin(∠F) = sin(∠C)
The sin(∠C) = opposite/hypotenuse
= |AB| / |AC|
= 12/20
= 3/5
= 0.6
So the answer is 0.6.</span>
Help please. ,,.,,.,.,.,.,.,.,
Umnica [9.8K]
It depends, are you trying to find area or perimeter?
Check the picture below.
so by graphing those two, we get that little section in gray as you see there, now, x = 6 is a vertical line, so we'll have to put the equations in y-terms and this is a washer, so we'll use the washer method.

the way I get the radii is by using the "area under the curve" way, namely, I use it to get R² once and again to get r² and using each time the axis of rotation as one of my functions, in this case the axis of rotation will be f(x), and to get R² will use the "farthest from the axis of rotation" radius, and for r² the "closest to the axis of rotation".

now, both lines if do an equation on where they meet or where one equals the other, we'd get the values for y = 0 and y = 1, not surprisingly in the picture.
![\displaystyle\pi \int_0^1\left( 3y-3y^2-\cfrac{y^2}{16}+\cfrac{y^4}{16} \right)dy\implies \pi \left( \left. \cfrac{3y^2}{2} \right]_0^1-\left. y^3\cfrac{}{} \right]_0^1-\left. \cfrac{y^3}{48}\right]_0^1+\left. \cfrac{y^5}{80} \right]_0^1 \right) \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{59\pi }{120}~\hfill](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cpi%20%5Cint_0%5E1%5Cleft%28%203y-3y%5E2-%5Ccfrac%7By%5E2%7D%7B16%7D%2B%5Ccfrac%7By%5E4%7D%7B16%7D%20%5Cright%29dy%5Cimplies%20%5Cpi%20%5Cleft%28%20%5Cleft.%20%5Ccfrac%7B3y%5E2%7D%7B2%7D%20%5Cright%5D_0%5E1-%5Cleft.%20y%5E3%5Ccfrac%7B%7D%7B%7D%20%5Cright%5D_0%5E1-%5Cleft.%20%5Ccfrac%7By%5E3%7D%7B48%7D%5Cright%5D_0%5E1%2B%5Cleft.%20%5Ccfrac%7By%5E5%7D%7B80%7D%20%5Cright%5D_0%5E1%20%5Cright%29%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%5Ccfrac%7B59%5Cpi%20%7D%7B120%7D~%5Chfill)