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3 years ago

A naturally occurring force related to two bidies in motion is force

1 answer:

german3 years ago

5 0

<span>1. Frictional force</span>

A naturally occurring force related to two bodies in motion is frictional force. Friction is a type of force which includes two bodies resisting each other –either motion of solid surfaces, fluid layers, material elements and compounds gliding against each other. They key point of this frictional force is that the two forces are in the opposite point of direction with each other. For example, when you are cold, as you rub your hands together notice that when your right hand is going upward, your left hand is downward and thus creates heat. That is one type of friction force outcome, the heat.

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What has a larger wavelength the color iolet or the color red?explain?

horsena [70]

Red has the longer wavelength. Wavelength and frequency are inversely related, so the longer the wavelength, the lower the frequency. This lower frequency is them perceived by our eye as the color red.

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3 years ago

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777dan777 [17]

To present your findings/data

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3 years ago

An object of mass m is dropped from height h above a planet of mass M and radius R .

Margarita [4]

Answer:

$v = \sqrt{2GM(\frac{1}{R+h)}-\frac{1}{R})}$

Explanation:

The initial mechanical energy of the object, when it is located at height h above the the planet, is just gravitational potential energy:

$E=U=\frac{GMm}{(R+h)}$

where

G is the gravitational constant

M is the mass of the planet

m is the mass of the object

R is the radius of the planet

h is the altitude of the object

When the object hits the ground, its mechanical energy will sum of potential energy and kinetic energy:

$E=\frac{GMm}{R}+\frac{1}{2}mv^2$

where

v is the speed of the object at the ground

Since the mechanical energy is conserved, we can write

$\frac{GMm}{R}+\frac{1}{2}mv^2=\frac{GMm}{R+h}$

and solving for v, we find

$\frac{GMm}{R}+\frac{1}{2}mv^2=\frac{GMm}{R+h}\\v = \sqrt{2GM(\frac{1}{R+h)}-\frac{1}{R})}$

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3 years ago

Four model rockets are launched in a field. The mass of each rocket and the

TiliK225 [7]

Answer: it is rocket 2

Explanation: I just took the test

Hope it's the right answer for you

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4 years ago

The general formula for kinetic energy is k = 0.5mv2 where k = kinetic energy, m = mass, and c = velocity. Solve k = 0.5mv2 for

tensa zangetsu [6.8K]

K = 0.5mv²

k = kinetic energy
m = mass
v = velocity
0.5 = 1/2

solve for v.

k = 1/2 * m * v²
(k * 2) / m = v²
√(2k/m) = √v²

√(2k/m) = v

There should have been a list of choices included in this problem.

v = √(2k/m)

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3 years ago