Answer:
a) y = 16.51 [m]
b) t = 1.83 [s]
Explanation:
To solve this problem we must use two kinematics equations, the first to determine the height to which the ball reaches, and the second equation to determine how long it lasts in the air.

where:
Vf = final velocity = 0
Vi = initial velocity = 18 [m/s]
g = gravity acceleration = 9.81[m/s^2]
t = time [s]
Note: the negative sign of the Equation indicates that the acceleration of gravity acts in the opposite direction to the movement of the ball. The final velocity is zero, since the ball reaches its maximum altitude when the velocity is zero.
Now replacing:
0 = (18)^2 - (2*9.81*y)
y = 16.51 [m]
b)

0 = 18 - (9.81*t)
t = 1.83 [s]
We have that the instantaneous power is

From the question we are told that
A 60 kg person runs up a 30° ramp
distance of 15 m up the ramp in 5.8 s.
t = 4.0 s?
Generally the equation for the Force is mathematically given as

Where

Therefore

Where

Now


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Answer:

Explanation:
The force experimented by a charge <em>q </em>in a uniform electric field <em>E</em><em> </em>is <em>F=qE</em>.
Newton's 2nd Law tells us that the relation between acceleration <em>a</em> a mass <em>m </em>experiments when a force <em>F </em>is applied to it is <em>F=ma</em>.
Combining these equations we have <em>am=qE</em>, and since we want the acceleration of the speck of dust, we substitute our values:

Answer:
I_2 = 0.146 A
Explanation:
The formula for current in an inductor is;
I_rms = V_rms/X_L
Where X_L is inductance wirh formula 2πfL
So, I_rms = V_rms/X_L
Applying this to the two generators, we have;
First generator;
I_1 = V_rms/(2π(f_1)L)
And I_2 = V_rms/(2π(f_2)L)
Thus, to find the current in the second generator, we divide eq 1 by eq 2;
So,
I_2/I_1 = [V_rms/(2π(f_2)L)]/[V_rms/(2π(f_1)L)]
Some values will cance out leaving us with;
I_2/I_1 = f_1/f_2
I_2 = I_1(f_1/f_2)
Plugging in the relevant values ;
I_2 = 0.56(1.2/4.6)
I_2 = 0.146 A
Answer:
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