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Leno4ka [110]
3 years ago
5

An automobile having a mass of 1,000 kg is driven into a brick wall in a safety test. The bumper behaves like a spring with cons

tant 5.90 ✕ 106 N/m and is compressed 2.63 cm as the car is brought to rest. What was the speed of the car before impact, assuming no energy is lost in the collision with the wall?
Physics
1 answer:
vlada-n [284]3 years ago
8 0

Answer:

v=2.02\frac{m}{s}

Explanation:

Assuming no energy lost, according to the law of conservation of energy, the kinetic energy of the automobile becomes potential energy after the crash:

K=U\\\frac{mv^2}{2}=\frac{kx^2}{2}

Here m is the automobile's mass, v is the speed of the car before impact, k is the "bumper" constant and x is the compression of the bumper due to the collision. Solving for v:

v=x\sqrt\frac{k}{m}\\v=2.63*10^{-2}m\sqrt{\frac{5.9*10^6\frac{N}{m}}{10^3kg}}\\v=2.02\frac{m}{s}

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nevsk [136]

Answer:

16.935 N

Explanation:

In order to make the box start moving, the level force applied on the box (F) must be greater than the force of static friction that keeps the box at rest, which is equal to

F_f = \mu_s (mg)

where

\mu_s = 0.5645 is the coefficient of static friction

(mg) = 30 N is the weight of the box

Therefore, the condition for F must be:

F \geq F_f\\F \geq \mu_k (mg)=(0.5645)(30 N)=16.935 N

So, the applied force must be greater than this value.

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What does the zigzag line in the circuit diagram represent? A. a source of electrical energy B. an electrical conductor C. an el
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Explanation:

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Why the dogs lays down next to the wood stove? Is it radiation,convection,conduction?
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A laser emits light at power 6.20 mW and wavelength 633 nm. The laser beam is focused (narrowed) until its diameter matches the
Ipatiy [6.2K]

Answer:

a) S = 1.69 10⁹ W/m², b)  P = 5.63 Pa , c) F = 20.6 10⁻¹² N

Explanation:

a) The intensity defined as the energy per unit area

    S = U / A

Area of ​​a circle is

    W = 6.2 mw = 6.2 10-3 W

    R = 1080 nm = 1080 10⁻⁹ m  = 1.080 10⁻⁶ m

   A = π R2

   A = π (1,080 10⁻⁶)²

   A = 3.66 10 -12 m²

   S = 6.2 10-3 / 3.66 10-12

   S = 1.69 10⁹ W / m²

b) The radiation pressure

   P = 1 / c (dU / dt) / A

   S = (dU / dt) / A

   

   P = S / c

   P = 1.69 10 9 / 3. 108

   P = 5.63 Pa

c) the definition of pressure is force over area

   P = F / A

   F = P A

   F = 5.63 3.66 10⁻¹²

   F = 20.6 10⁻¹² N

d) for this we use Newton's second law

   F = ma

   a = F / m

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