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Leno4ka [110]
3 years ago
5

An automobile having a mass of 1,000 kg is driven into a brick wall in a safety test. The bumper behaves like a spring with cons

tant 5.90 ✕ 106 N/m and is compressed 2.63 cm as the car is brought to rest. What was the speed of the car before impact, assuming no energy is lost in the collision with the wall?
Physics
1 answer:
vlada-n [284]3 years ago
8 0

Answer:

v=2.02\frac{m}{s}

Explanation:

Assuming no energy lost, according to the law of conservation of energy, the kinetic energy of the automobile becomes potential energy after the crash:

K=U\\\frac{mv^2}{2}=\frac{kx^2}{2}

Here m is the automobile's mass, v is the speed of the car before impact, k is the "bumper" constant and x is the compression of the bumper due to the collision. Solving for v:

v=x\sqrt\frac{k}{m}\\v=2.63*10^{-2}m\sqrt{\frac{5.9*10^6\frac{N}{m}}{10^3kg}}\\v=2.02\frac{m}{s}

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If you calculate W, the amount of work it took to assemble this charge configuration if the point charges were initially infinit
sp2606 [1]

Answer:

W = 0×(kq2L)

Explanation:

We know that the work to assemble a charge configuration of two charges a distance r from each other is simply W = kq2/r

If we want to assemble three charges A, B, and C. It's necessary to consider the distances between them

WABC = kq2/(rAB + rAC + rBC)

So, to assemble four charges A, B, C, & D....

WABCD = kq2/(rAB + rAC + rAD + rBC + rBD + rCD)

 

Considering a square charge configuration with sides L, such as in figure attached A, B, & C are positive & D is negative

rAB = L

rAC = L√2

rAD = L (-)

rBC = L

rBD = L√2 (-)

rCD = L (-)

⇒ W = kq2/(L + L√2 + (-L) + L + (-L√2) + (-L)

⇒ ∴ W = 0 × (kq2/L)

This way, working through each option...  

(a)

The positive charges are equidistant from each other at a distance of L.

rAB = L

rAC = L

rAD = ½L⋅sin(60) (-)

rBC = L

rBD = ½L⋅sin(60) (-)

rCD = ½L⋅sin(60) (-)

Wa = kq2/(3L - (3/2)L⋅(0.866))

⇒ ∴ Wa = (1/1.7) × (kq2/L) = (0.5879)× (kq2/L)

(b)

rAB = L

rAC = 2L

rAD = 3L (-)

rBC = L

rBD = 2L (-)

rCD = L (-)

Wb = kq2/(4L - 6L)

⇒ ∴ Wb = (-1/2) × (kq2/L) = (-0.5)× (kq2/L)

(c)

The factor doesn't matter, so Wc = 0 × (kq2/L)

In this case, the greater work is actually the less work. Therefore, the positive work represents the amount of work the system actually exhibits, that we don't have to do. If there is negative work, we have to make up that work in order to place the charges as desired.  

This way, charge configuration (a) requires the least amount of work.

5 0
3 years ago
A truck covers 40.0 m in 7.45 s while uniformly slowing down to a final velocity of 3.50 m/s.
astra-53 [7]

Answer:

(A) Original velocity will be 7.244 m /sec

(B) Acceleration will be  -0.5026m/sec^2

Explanation:

We have given distance covers by truck s = 40 m

Time taken by truck to cover this distance t = 7.45 sec

Final velocity v = 3.50 sec

According to second equation of motion

S=ut+\frac{1}{2}at^2

40=u\times 7.45+\frac{1}{2}\times a\times 7.45^2

7.45u+27.751a=40-----eqn 1

According to first equation of motion

v = u + at

So 3.5=u+7.45a-----eqn2

Solving equation 1 and 2

a = -0.5026m/sec^2

And u = 7.244 m /sec

(A) Original velocity will be 7.244 m /sec

(B) Acceleration will be

-0.5026m/sec^2

6 0
4 years ago
A motorcycle of 170 kg is moving with a velocity 25m/ . Calculate the kinetic energy
topjm [15]

Answer: 53125joules

Explanation: The formula for kinetic energy is 1/2mv^2.

So we would have

1/2[(170)(25x25)]=53125

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3 years ago
When the moon slowly moves away from the earth.How is it affecting the gravitational force between the earth and the moon?
sukhopar [10]
Well, think about how the tides will be affected when the moon moves farther away. If the moon first started off very close the earth, we would have more tsunamis. (Scientists have found that the moon has possibly been closer to earth long ago.) While it moves away, soon there will no longer be many tides.
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3 years ago
Which of these chemical compounds is generated during the process of cellular respiration
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"Cellular respiration, the process by which organisms combine oxygen with foodstuff molecules, diverting the chemical energy in these substances into life-sustaining activities and discarding, as waste products, carbon dioxide and water." ~https://www.britannica.com/science/cellular-respiration


8 0
4 years ago
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