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4 years ago

How many moles of o are in 15.0 mol fe(no3)3?

Chemistry

2 answers:

krok68 [10]4 years ago

7 0

N[Fe(NO₃)₃]=15.0 mol

n(O)=3×3×n[Fe(NO₃)₃]=9n[Fe(NO₃)₃]

n(O)=9×15.0=135.0 mol

Afina-wow [57]4 years ago

4 0

Answer : The number of moles of oxygen atoms are 135 moles.

Explanation : Given,

Moles of $Fe(NO_3)_3$ = 15.0 mole

The given chemical formula is, $Fe(NO_3)_3$

By the mole concept:

In $Fe(NO_3)_3$ , there are 1 mole of iron (Fe) atom, 3 moles of nitrogen (N) atoms and 9 moles of oxygen (O) atoms.

As, 1 mole of $Fe(NO_3)_3$ contains 9 moles of oxygen atoms

So, 15.0 moles of $Fe(NO_3)_3$ contains $15.0\times 9=135$ moles of oxygen atoms.

Hence, the number of moles of oxygen atoms are 135 moles.

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