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viktelen [127]
3 years ago
12

The combustion of 44.45 grams of a hydrocarbon gas mixture releases 2,649 kJ of heat. How much energy, in kWh, will the combusti

on of exactly one pound of this hydrocarbon gas produce? There are 453.592 g in 1 lb. Please express your answer to the appropriate number of significant figures. Your Answer:
Chemistry
1 answer:
Naddika [18.5K]3 years ago
3 0

Explanation:

It is given that 44.45 g of hydrocarbon gas produces 2649 kJ or 2649 \times 10^{3} J of heat.

Also here, 1 lb = 453.592 g.

Therefore, amount of energy released by 453.592 g of hydrocarbon gas will be calculated as follows.

              \frac{2649 \times 10^{3} J \times 453.592 g}{44.45 g}

             = 27.03 \times 10^{6} J

It is known that 1 J = 2.778 \times 10^{-7} Kwh.

Hence, 27.03 \times 10^{6} J = 27.03 \times 10^{6} J \times 2.778 \times 10^{-7} Kwh/J

                              = 7.508 Kwh

Thus, we can conclude that the combustion of exactly one pound of this hydrocarbon gas produce 7.508 Kwh energy.

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This problem is simply converting the concentration from molality to molarity. Molality has units of mol solute/kg solvent, while molarity has units of mol solute/L solution.

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