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NemiM [27]
3 years ago
8

What is an atomic number? An atomic mass?

Chemistry
2 answers:
Svetradugi [14.3K]3 years ago
8 0

Answer:

Atomic number

The number of protons in the nucleus of an atom.

Atomic Mass

The mass of an atom of a chemical element expressed in atomic mass units.

mrs_skeptik [129]3 years ago
4 0

Answer:

The atomic number is the number of the elements inside the periodic table and the mass is the weight or a number under the elements.

Explanation:

Correct me if I am wrong

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What is the kinetic energy of a 2kg rabbit hopping at a speed of 1.25 m/s?1,5625J

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Your chemistry lab partner is interested in studying how industrial chemicals can pollute the environment. What type of chemistr
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What is the Environmental Lapse Rate?
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The rate at which the air temperature changes with height in the atmosphere surrounding a cloud or a rising parcel of air. The overall average rate is a decrease of about 6.5°C/km, but the rate varies greatly in different regions of the world, in different airstreams, and at different seasons of the year.

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What is true about a solution of 1.0 M HF? HF has a higher [OH-] than a solution of 1.0 M HCl. HF has a lower pH than a solution
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<span>HF has a higher [OH-] than a solution of 1.0 M HCl. is the answer</span>
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Read 2 more answers
A 10.000g ice cube is added to 100.000g of water at 80.0 oC in a calorimeter. The final temperature of the water in the calorime
Ket [755]

<u>Answer:</u> The amount of heat needed to melt the ice cube is 6.083 kJ

<u>Explanation:</u>

The processes involved in the given problem are:

1.)H_2O(s)(0^oC,273K)\rightarrow H_2O(l)(0^oC,273K)\\2.)H_2O(l)(0^oC,273K)\rightarrow H_2O(l)(65.5^oC,338.5K)

  • <u>For process 1:</u>

To calculate the amount of heat required to melt the ice at its melting point, we use the equation:

q_1=m\times \Delta H_{fusion}

where,

q_1 = amount of heat absorbed = ?

m = mass of ice = 10.000 g

\Delta H_{fusion} = enthalpy change for fusion = 334.16 J/g

Putting all the values in above equation, we get:

q_1=10.000g\times 334.16J/g=3341.6J

  • <u>For process 2:</u>

To calculate the heat required at different temperature, we use the equation:

q_2=mc\Delta T

where,

q_2 = heat absorbed

m = mass of ice = 10.000 g

c = specific heat capacity of water = 4.184 J/g.°C

\Delta T = change in temperature = T_2-T_1=[65.0-0]^oC=65.5^oC

Putting values in above equation, we get:

q_2=10.000g\times 4.184J/g.^oC\times 65.5^oC\\\\q_2=2741.83J

Total heat absorbed = q_1+q_2

Total heat absorbed = [3341.6+2741.83]J=6083.43J=6.083kJ

Hence, the amount of heat needed to melt the ice cube is 6.083 kJ

4 0
4 years ago
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