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Natali5045456 [20]
3 years ago
15

Andrew kicks a ball along a straight path. The ball rolls straight forward for 13.2 meters. Then Andrew kicks the ball straight

back. The ball rolls back along the same path for 9.5 meters. What distance did the ball travel?
3.7 meters
0 meters
22.7 meters
125 meters
Physics
1 answer:
hram777 [196]3 years ago
4 0

Answer:

22.7 meters

Explanation:

Let's remind the difference between distance and displacement:

- distance: the total distance travelled by an object in all its paths

- displacement: the different between the final and initial position of the object

In this case, the problem asks to find the distance covered by the ball. This will be the sum of the distances covered by the ball in each part of its motion, therefore:

d=13.2 m+9.5 m=22.7 m

(instead, the displacement will be the difference between the final and initial position of the ball, therefore:

d=13.2 m-9.5 m=3.7 m)

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3.26m

Explanation:

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A truck undergoes a constant acceleration of 2.0 meters/second2 on a highway that slopes upward at an angle of 30.0° to the hori
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The age of a piece of wood from an archeological site is to be determined using the Carbon-14 method. The activity of the sample
Bezzdna [24]

Answer:

4589.05 year

Explanation:

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We know that half life T=\frac{0.693}{\lambda }

\lambda =\frac{0.693}{5730}=1.2094\times 10^{-4}\ per\ year

So 0.574=e^{-1.2094\times 10^{-4}t}

e^{1.2094\times 10^{-4}t}=\frac{1}{0.574}=1.742

{1.2094\times 10^{-4}t}=ln1.742=0.555

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7 0
3 years ago
A railroad train is traveling at a speed of 26.0 m/s in still air. The frequency of the note emitted by the locomotive whistle i
olga55 [171]

Answer: 0.757m; 0.881m; 432.70Hz; 371.89Hz

Explanation:

Give the following :

Velocity of train (Vt) = 26m/s

Frequency of sound (Fs) = 420Hz

Speed of sound (Vs) = 344m/s

1) wavelength = (Vs - Vt) / Fs

Wavelength = (344 - 26) / 420 = 318/420 = 0.757m

11) Wavelength = (Vs + Vt) / Fs

Wavelength = (344 + 26) / 420 = 370/420 = 0.881m

111) According to the doppler effect :

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Fl = frequency of listener ; fs = frequency of sound source ; V = speed of sound ; Vl = Velocity of listener ; Vs = speed of sound source

Vs = - ve (train moving towards listener)

Fl = [(V + Vl) / (V + Vs)] * fs

Fl = [(344 + 0) / (344 - 26)] * 400

Fl = (344 / 318) * 400 = 432.70Hz

1V) Vs = + ve (train moving away listener)

Fl = [(V + Vl) / (V + Vs)] * fs

Fl = [(344 + 0) / (344 + 26)] * 400

Fl = (344 / 370) * 400 = 371.89Hz

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