How do elements change as you move to the right along a row in the periodic table

Match each space mission with the correct milestone.

MrRissso [65]

Matching each space mission with the correct milestone

First animal in space ____________ Sputnik 2
first person in space ____________ Vostok 1
first person on the moon _________ Apollo 11
first man-made object in space ____ Sputnik 1
first American in space __________ Freedom 7
first space station ______________ Salyut

<h3>Meaning of space mission</h3>

A space mission is a mission that takes an individual, animal, a thing or material out of earth using a spaceship. This mission is always carried out with a desire to find out more about the galaxy earth is a member of and to learn about other planets.

In conclusion, the list above is the accurate Matching of each space mission with the correct milestone.

Learn more about Space mission: brainly.com/question/1298543

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6 0

2 years ago

Read 2 more answers

Two point charges of +2.0 μC and -6.0 μC are located on the x-axis at x = -1.0 cm and x = +2.0 cm respectively. Where should a t

lyudmila [28]

Answer:

x = -3 cm

Explanation:

The electrical potential is the sum of the potentials of each charge

V = k ∑ $q_{i} / r_{i}$

let's apply this to our case where the potential is V = 0 for x = 0

0 = k (q₁ / (x₁-0) + q₂ / (x₂-0) + q₃ / (x₃-0))

in our case

q₁ = + 2.0 10⁻⁶ C

q₂ = - 6.0 10⁻⁶ C

q₃ = + 3.0 10⁻⁶ C

x₁ = -1.0 cm = 1.0 10⁻² m

x₂ = +2.0 cm = 2.0 10⁻² m

we substitute in the equation

0 = k (2 10⁻⁶ / 1 10⁻² - 6 10⁻⁶ / 2 10⁻² + 3 10⁻⁶ / x)

3 10⁻⁶ / x = 2 10⁻⁴ - 3 10⁻⁴

3 10⁻⁶ / x = -1 10⁻⁴

x = - 3 10⁻² m

x = -3 cm

7 0

3 years ago

Use the work—energy theorem to solve each of these problems. You can use Newton's laws to check your answers. Neglect air resist

andreyandreev [35.5K]

Answer:

a) It is moving at $43.15\frac{m}{s^{2}}$ when reaches the ground.

b) It is moving at $101.44\frac{m}{s^{2}}$ when reaches the ground.

Explanation:

Work energy theorem states that the total work on a body is equal its change in kinetic energy, this is:

$W=K_f-K_i$ (1)

with W the total work, Ki the initial kinetic energy and Kf the final kinetic energy. Kinetic energy is defined as:

$K=\frac{mv^2}{2}$ (2)

with m the mass and v the velocity.

Using (2) on (1):

$W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}$ (3)

In both cases the total work while the objects are in the air is the work gravity field does on them. Work is force times the displacement, so in our case is weight (w=mg) of the object times displacement (d):

$W=Fd=wd=mgd$ (4)

Using (4) on (3):

$mgd=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}$ (5)

That's the equation we're going to use on a) and b).

a) Because the branch started form rest initial velocity (vi) is equal zero, using this and solving (5) for final velocity:

$v_f=\sqrt{\frac{2mgd}{m}}=\sqrt{2gd}=\sqrt{2*9.8*95}$

$v_f=43.15\frac{m}{s^{2}}$

b) In this case the final velocity of the boulder is instantly zero when it reaches its maximum height, another important thing to note is that in this case work is negative because weight is opposing boulder movement, so we should use -mgd:

$-mgd=-\frac{mv_i^2}{2}$