Answer:2
Explanation:
Given
and and
are the acceleration of 1 and 2
Suppose T is the Tension
then for block 2
For block 1
equate 1 and 2
where
thus we can see that a is less than g
therefore
A railroad train is traveling at a speed of 26.0 m/s in still air. The frequency of the note emitted by the locomotive whistle i
1 answer:
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The magnetic field at the center of the circular loop is 3.24 x 10⁻⁴ T.
<h3>Current in the wire</h3>The current in the wire is calculated as follows;
V = IR
I = V/R
I = 16.7/0.251
I = 66.53 A
<h3>Magnetic field at the center of the loop</h3>The magnetic field at the center of the circular loop is calculated as follows;
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Answer:
The expression for the initial speed of the fired projectile is:
And the initial speed ratio for the 9.0mm/44-caliber bullet is 1.773.
Explanation:
For the expression for the initial speed of the projectile, we can separate the problem in two phases. The first one is the moment before and after the impact. The second phase is the rising of the ballistic pendulum.
First Phase: Impact
In the process of the impact, the net external forces acting in the system bullet-pendulum are null. Therefore the linear momentum remains even (Conservation of linear momentum). This means:
(1)
Second Phase: pendular movement
After the impact, there isn't any non-conservative force doing work in al the process. Therefore the mechanical energy remains constant (Conservation Of Mechanical Energy). Therefore:
(2)
The height of the pendulum respect L and θ is:
(3)
Using equations (1),(2) and (3):
(4)
The initial speed ratio for the 9.0mm/44-caliber bullet is obtained using equation (4):