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3 years ago

8

David wants to buy a CD that regularly cost $12. The CD is Advertised as 1/4 off the regular price. Before tax, what is the cost

of the CD?

2 answers:

Pani-rosa [81]3 years ago

6 0

The CD will have be £3 off so it would cost £9

aev [14]3 years ago

5 0

Hey You!

12/4 = 3

12 - 3 = 9

So, before tax, the CD costs $9, as 1/4 of 12 is 9.

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Which expression is equivalent to 3.5x+1.5x+2-1/2

MrRissso [65]

The most simplified version would be:
$5x+1.5$

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3 years ago

Please procedure and solution <br><br>2 x |-6|-3 x |2|+|-14|=

lora16 [44]

Applying the rule of modulus for given values, the expression will result to 20.

<h3>What is Modulus or Absolute Values</h3>

The modulus of a value for example |a|=a if a is greater than or equal to zero

and also

|a|=-a if a is less than zero

In the expression given; the modulus of -6 written as

|-6|=-(-6) this is because the value is less than zero

The modulus of 2 written as; |2|=2 this is because the value is greater than zero. and;

|The modulus of -14 written as; |-14|= -(-14) since the value is less than zero.

Hence, we can rewrite the expression as;

we deal with multiplication first following the rules of BODMAS

2×-(-6)-3×2+[-(-14)]

2×6-6+14

and thus adding values

12+14-6

and finally we subtract;

26-6

which will results to the solution of 20.

5 0

2 years ago

3.11 A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the nu

djverab [1.8K]

Answer:

Probability distribution for x:

$P(x=0)=0.3644\\\\P(x=1)=0.4373\\\\P(x=2)=0.1749\\\\P(x=3)=0.0233\\\\$

Step-by-step explanation:

We can model the number of defective sets in the group of TV sets (variable x) as a binomial variable, with sample size=3 and probability of success p=2/7≈0.2857.

The probability of k defective sets in the group is:

$P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}$

So, we have this probabilty distribution for x:

$P(x=0) = \dbinom{3}{0} p^{0}q^{3}=1*1*0.3644=0.3644\\\\\\P(x=1) = \dbinom{3}{1} p^{1}q^{2}=3*0.2857*0.5102=0.4373\\\\\\P(x=2) = \dbinom{3}{2} p^{2}q^{1}=3*0.0816*0.7143=0.1749\\\\\\P(x=3) = \dbinom{3}{3} p^{3}q^{0}=1*0.0233*1=0.0233\\\\\\$

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3 years ago

A cement walk 3 ft wide is placed around the outside of a rectangular garden plot that is 20ft by 30ft. Find the cost of the wal

Inessa05 [86]

Let us calculate the area of the walk.

Since the width of the walk is 3 feet, and the walk will be placed all the 4 sides,

Length of the plot including walk = 20 + (2 × 3) = 20 + 6 = 26 feet.

Breadth of the plot including walk = 30 + (2 × 3) = 36 feet.

Area of the plot including walk = 26 × 36 square feet.

Area of the plot = 20 × 30 square feet.

Area of the walk = (26 × 36) - (20 × 30)

= 936 - 600

= 336 square feet.

= $\frac{336}{3(3)}$ square yards

= 37.3 square yards

Cost of the walk per square yard = $12.25.

Therefore, total cost of the walk = 12.25 × 37.3 = $456.92.

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3 years ago

What is an explicit formula for the geometric sequence 64,16,4,1,... where the first term

olya-2409 [2.1K]

Answer:

A

Step-by-step explanation:

The explicit formula for a geometric sequence is

f(n) = f(1) $(r)^{n-1}$

where f(1) is the first term and r the common ratio

Here f(1) = 64 and r = $\frac{f(2)}{f(1)}$ = $\frac{16}{64}$ = $\frac{1}{4}$ , then

f(n) = 64 $(\frac{1}{4}) ^{n-1}$ → A

7 0

2 years ago