Given the following method definitions: void mystery(double a) { System.out.print("double! "); } void mystery(int a) { System.ou
t.print("int! "); } What will be the output of the following code? mystery(1); mystery(1.0); Select one: a. It is impossible to predict
b. int! double!
c. Duplicate function names results in a compiler error.
d. double! int!
The correct answer to the following question is option "b".
Explanation:
The method having the same name but the arguments have different so it is called method overloading. It is a part of the object-oriented programming language (oops).
In the given code we define same method two times that is "mystery()". but in this method, we pass two different parameters. For the first time, we pass a double variable that is "a" as a parameter. In the second time, we pass an integer variable that is "a" as a parameter and in both functions, we write some codes.
In the calling time, we call function two times. In first time calling we pass an integer value that is "1" and second time calling we pass double value that is "1.0". So the output of this code is "int! double!".
Answer: Sounds like you are talking about “Distributed memory systems” which use multiple computers to solve a common problem, with computation distributed among the connected computers (nodes) and using message-passing to communicate between the nodes.
Always the getaway is the first device in a network, and for that was assigned this IP address 192.168.2.1, is the first address of the block, a network getaway gives us interoperability between networks and contains devices, and is a protocol translator, this is a piece of hardware used for telecommunication networks.
