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Anna71 [15]
3 years ago
15

Translate the sentence into an equation. Four more than a number is 12.

Mathematics
2 answers:
Lapatulllka [165]3 years ago
5 0
More than means addition
lets call our number 'x'
is means the equal sign

so we would get 

x + 4 = 12
D
I am Lyosha [343]3 years ago
5 0
x+4=12
..............
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Find all the angles listed. also list all of the lines that are secants, chords and tangents
Tanzania [10]

Answer:

Secants – 1. <CBG 2. <AGF 3. <ABD

Tangent – 1. <CDE

Chords – 1. <BD 2. <DF 3. <BG 4. <BF 5. <GD 6. <FG

Angles – 1. 45 2. 75 3. 35 4. 70 5. 75 6. 55 7. 50 8. 25 9. 35 10. 70 11. 50 12. 25 13. 70 14. 50. 15. 60 16. 85 17. 95 18. 85 19. 95

Step-by-step explanation:

4 0
2 years ago
From a pool of 12 candidates, the offices of president, vice-president, secretary, and treasurer will be filled. In how many dif
Romashka [77]

Answer:

11,880 different ways.

Step-by-step explanation:

We have been given that from a pool of 12 candidates, the offices of president, vice-president, secretary, and treasurer will be filled. We are asked to find the number of ways in which the offices can be filled.

We will use permutations for solve our given problem.

^nP_r=\frac{n!}{(n-r)!}, where,

n = Number of total items,  

r = Items being chosen at a time.        

For our given scenario n=12 and r=4.

^{12}P_4=\frac{12!}{(12-4)!}

^{12}P_4=\frac{12!}{8!}

^{12}P_4=\frac{12*11*10*9*8!}{8!}

^{12}P_4=12*11*10*9

^{12}P_4=11,880

Therefore, offices can be filled in 11,880 different ways.

     

   

3 0
3 years ago
(a) Suppose Y1(t) is a solution of an autonomous system dY/dt = F(Y). Show that Y2(t) = Y1(t +t0) is also a solution for any con
alexandr1967 [171]

Answer:

Step-by-step explanation: see attachment

6 0
3 years ago
Find the missing values assuming continuously compounded interest. (Round your answers to two decimal places.)
alexdok [17]

Answer:

<h2>$3448.81</h2>

Step-by-step explanation:

Using the compound interest formula to calculate the amount compounded after 10years.

A = P(1+r)^{nt}

P = principal  = $2000

r = rate (in %) = 5.6%

t = time (in years) = 10years

n = 1year = time used in compounding

A = 2000(1+0.056)^{10} \\A = 2000(1.056)^{10}\\A = 2000*1.7244046\\A = 3448.81 (to\  2dp)

Amount compounded after 10 years is $3448.81

4 0
3 years ago
Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
Tresset [83]

Answer:

Step-by-step explanation:

Hello!

Three samples of components manufactured are taken per day. They are classified as:

D: "Conforming (suitable for its use)"

E: "Downgraded (unsuitable for the intended purpose but usable for another purpose)"

F: "Scrap (not usable)"

This classification includes the three events that may occur in your sample space S. The experiment consists in recording the categories of the three parts tested in a day.

a. List the 27 outcomes in the sample space.

The possible outcomes in the space sample are the combinations of the three events. To avoid using the same letters as in the following questions I've named the evets as D, E, and F

S={DDD, DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EEE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FDD, FEE}

b. Let A be the event that all the parts fall into the same category. List the outcomes in A.

A: "All the parts fall into the same category"

You have three possible outcomes for this event, that the three compounds are conforming, "DDD", that the three are unconforming, "EEE", or that the three compounds are scrap, "FFF". There are only three possible outcomes for this event.

S={DDD, EEE, FFF}

c. Let B be the event that there is one part in each category. List the outcomes in B.

B: "There is a part in each category"

This means, for example, The first one is conforming "D", the second one is unconforming "E" and the third one is scrap "F", then the first one may be unconforming "E", the second one is conforming "D" and the thirds one is scrap "F", and so on, you have 6 possible outcomes for this event:

S={DEF, DFE, EDF, EFD, FDE, FED}

d. Let C be the event that at least two parts are conforming. List the outcomes in C.

C: "At least two parts are conforming"

For this event, you can have two of the compounds to be considered conforming or the three of them.

S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

A total of 7 combinations fit this event.

I hope you have a SUPER day!

6 0
2 years ago
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