9514 1404 393
Answer:
5 seconds
Step-by-step explanation:
Suppose the front parts of the trains meet at point A. Since both are the same length and traveling the same speed, each will pass point A in time ...
time = distance/speed
time = (1/18 mi)/(40 mi/h) = (1/720 h) × (3600 s)/(1 h) = 5 s
That is, the rear part of each train will be at point A 5 seconds after the front part.
The rear parts will pass each other 5 seconds after the front parts meet.
Answer:
Answer:
t ≅ 5.09 min
Step-by-step explanation:
we have that if in 4000 L/sol there is 132 kg salt and the pumping speed is 12L/s, we must find how much of salt is pumping per second and then find the amount of salt remaining
12L/s*132kg salt/4000L = 0.396 Kg salt/s, this means that 0.396 kg per second comes out , It should be found that the amount of salt must be drained so that only 11 kg of salt remain
132kg salt - 11 kg salt = 121 kg salt, so
121Kg salt*s/0.396Kg salt ≅ 305.55 s ⇒ 305.55s*min/60s ≅ 5.09 min
Step-by-step explanation:
I am assuming you want to find the simplest form of the inequality.
1.
2.
3.
1. Start
2. Subtract 9 from each side
3. Divide both sides by 3
Given:
64 total students
x = drama club students
y = yearbook club students
x = y + 10
y = 64 - x
y = 64 - x
y = 64 - (y + 10)
y = 64 - y - 10
y + y = 64 - 10
2y = 54
2y/2 = 54/2
y = 27
x = y + 10
x = 27 + 10
x = 37
To check:
x + y = 64
37 + 27 = 64
64 = 64
Answer:
a) 7
b) -8.2
c) 0
d) -7
e) -1 3/4
f) 121
Step-by-step explanation:
Just put the opposite for each one. The absolute value is the distance away from 0.
