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dimaraw [331]
3 years ago
13

Can you tell me important facts about Peggy A. Whitson?

Engineering
2 answers:
Mnenie [13.5K]3 years ago
7 0

Answer:

Peggy Annette Whitson was born February 9, 1960, Mount Ayr, Iowa, U.S.

She was the first female commander of the International Space Station.

She holds the record among American astronauts and among women for spending the most time in space, nearly 666 days.

She received a B.S. in biology and chemistry from Iowa Wesleyan College in Mount Pleasant, Iowa, in 1981 and a doctorate in biochemistry from Rice University in Houston in 1985.

She flew into space for the first time on June 5, 2002, as a flight engineer on Expedition 5 to the ISS, aboard the space shuttle Endeavour on mission STS-111.

She, from 2009 to 2012, Whitson was chief of the Astronaut Office, which oversees all NASA astronaut activities, including crew selection and training.

She was the first woman and the first civilian to hold that position.

She was sent into space 3 times.

Her total of 10 career spacewalks and their combined duration of 60 hours 21 minutes were records for a female astronaut.

She retired from NASA in 2018.

Nat2105 [25]3 years ago
6 0

Answer:

- She’s A Biochemist

- She’s An Accomplished Space Chef

- She holds the record for most time spent in a space station for an American astronaut — of any gender.

- She became the first woman to command the International Space Station twice.

- She made apple pie out of tortillas

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You are given a rectangular piece of cloth with dimensions X by Y, where X and Y are positive integers, and a list of n products
Bond [772]

The proof that recursion is exponential and that dynamic programming is polynomial is given by the formula;

P(x,y) = max{

P(x,y)

max (1 <= h <= X) { P[h, Y] + P(X - h, Y) }

max (1 <= v <= Y) { P[X, v] + P[X, Y - v] }

}

To prove that the recursion is exponential and that dynamic programming is polynomial. we will do so as follows;

Let us first have the assumption that the cloth is in such a manner that  either way, a product can be oriented. This implies that that after a cut, we will now have two pieces of cloth.

Now, we will make a list of the side lengths of the products that can fit in the piece after which we will consider a vertical cut for each of the side length as well as a horizontal cut for each of the side length, then we apply the same algorithm to each of the two resulting pieces.  

Thus, after the point above, it is likely true that in some instances, there may be a place to cut that is not at a product side length. However, It might be better for us to make a list of lengths composed of one or more pieces side by side as long as the sum is less than the length of the side being considered.

 

Lastly, we would note that this recursive approach is not limited to just two -dimensional problems as It could also be applied to a single or more than two dimensions. A useful proof would be to prove it for one dimension, then assuming it is true for n dimensions, prove it is true for n + 1 dimensions.

Thus;

P(x,y) = max{

P(x,y)

max (1 <= h <= X) { P[h, Y] + P(X - h, Y) }

max (1 <= v <= Y) { P[X, v] + P[X, Y - v] }

}

Read more at; brainly.com/question/11665190

3 0
3 years ago
A cylindrical tank is required to contain a gage pressure 670 kPakPa . The tank is to be made of A516 grade 60 steel with a maxi
RSB [31]

Answer:

The minimum thickness t of the wall is 0.00446 mm

Explanation:

Solution

Given that

Pressure =670kPa = 0.670

σ allowable normal stress = 150 MPa

Inner diameter = 2mm

Steel = A516 grade 60

Now,

Since the hoop stress is twice the longitudinal stress, the cylindrical tank is more likely to fail from the hoop stress.

Thus

σ allowable = σₙ = pμ/t

=p (d/2)

150 MPa =0.670MPa * 2/2/t

=0.67/t

t=0.67/150

t =0.00446 mm

8 0
4 years ago
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5 0
3 years ago
Problem: design the following rectangular floor beam for a building.
sammy [17]

Answer:

Area required = 9.5 ft²

Explanation:

Step by step explanation is given in the attached document.

8 0
3 years ago
Read 2 more answers
Consider a refrigerator that consumes 320 W of electric power when it is running. If the refrigerator runs only one quarter of t
Semenov [28]

Answer:

B. $5.18

Explanation:

Cost of electricity per kWh = $0.09

Power consumption of refrigerator = 320W = 320/1000 = 0.32kW

In a month (30 days) the refrigerator works 1/4 × 30 days = 7.5 days = 7.5 × 24 hours = 180 hours

Energy consumed in 180 hours = 0.32kW × 180h = 57.6kWh

Cost of electricity of 57.6kWh energy consumed by the refrigerator = 57.6 × $0.09 = $5.18

3 0
4 years ago
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