Answer:
f = 628.32 lb
t = 2513.28 lb-inc
Explanation:
given data:
θ = 45°
outside radius = 6 inch
inside radius = 4 inch
coefficient of friction = 0.4
max pressure = 100 psi
a) determine force required for applying one pad
f =
f =
f = 628.32 lb
b) torque capacity (t)
t =
t = 0.4 *628.32*5
torque = 1256.64 lb-inc
for both pad = 2 * 1256.64 =2513.28 lb-inc
Answer:
The time required to reduce the diameter of solid spherical ball from 2 cm to 0.50 cm = 61.60 hours
Explanation:
Given that:
The bulk gas temperature T = 347 K
The pressure = 1.0 atm
Molecular weight of naphthalene = 128 g/mole
density of the solid = 1.145 g/cm³
diffusivity in the air of coefficient = 8.19 × 10 ⁻⁶ m²/s
vapor pressure = 5.0 Torr (666 Pa)
The shape of the ball in this given study is spherical. So, the first step we need to carry out is to state the general differential equation for the mass transfer in the system of the spherical coordinates. After that , we will make use of simplified differential expression form of Fick's Flux. From there we'll determine the surface concentration (c) of the species and finally determine the material balance equation on the naphthalene which will be used in solving the time required to reduce the diameter from 2.0 cm to 0.50cm.
THE DETAILED EXPLANATION OF WHAT WE JUST SAID CAN BE SEEN IN THE ATTACHED IMAGES BELOW.
Answer: hello attached below is the diagram which is part of your question
Total entropy change = entropy change in cold reservoir + entropy change in hot reservoir = -0.166 + 0.083 = -0.0837 kj/k it violates Clausius increase of entropy which is Sgen > 0
Explanation:
Clausius statement states that it is impossible to transfer heat energy from a cooler body to a hotter body in a cycle or region without any other external factors affecting it .
applying the increase in entropy principle to prove this
temp of cold reservoir (t hot)= 600 k
temp of hot reservoir(t cold) = 1220 k
energy (q) = 100 kj
total entropy change = entropy change in cold reservoir + entropy change in hot reservoir = -0.166 + 0.083 = -0.0837 kj/k
entropy change in cold reservoir = Q/t cold = 100 / 600 = -0.166 kj/k
entropy change in hot reservoir = Q / t hot = 100 / 1220 = 0.083 kj/k
hence it violates Clausius inequality of increase of entropy principle which is states that generated entropy has to be > 0