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AnnyKZ [126]
3 years ago
11

Suppose that the president of a small island nation has decided to increase government spending by constructing three beach reso

rts to attract tourists. The legislation was enacted without any delay. From here, planning will take 6 months and construction will take 2 months. Which of the following is true? Choose one: A. This policy is contractionary. B. The Laffer curve would be used to recommend this policy. C. The planning and construction of the resorts represent a recognition lag of this policy. D. This policy shows an example of automatic stabilizers taking effect. E. The planning and construction of the resorts represent an impact lag of this policy.
Engineering
1 answer:
Mila [183]3 years ago
3 0

Answer:

Option E

The planning and construction of the resorts represent an impact lag of this policy.

Explanation:

Whereas the legislation was enacted without any delay but planning takes six months and construction taking 2 months, it means the policy has a lag. Therefore, option E, the planning and construction of the resorts represent an impact lag of this policy.

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BE-40 What is a characteristic of a catamaran hull?
Nat2105 [25]

Answer:

<em>A stable ride</em>

Explanation:

A Catamaran hull is a form of sea craft invented by the Austronesian peoples, the invention of the Catamaran hull enabled these people to sail across the sea in their expansion to the islands of the Indian and Pacific Oceans. Catamaran has multiple hulls, usually two parallel hulls of equal size. This geometric feature gives the craft an increased stability because,<em> it derives extra stability from its wide beam, in the place of a ballasted keel employed in a regular monohull sailboat. </em>A Catamaran hull will require four times the force needed to capsize it, when compared to an equivalent monohull.

8 0
3 years ago
A gas cylinder is connected to a manometer that contains water. The other end of the manometer is open to the atmosphere, which
horrorfan [7]

Answer: the absolute static pressure in the gas cylinder is 82.23596 kPa

Explanation:

Given that;

patm = 79 kPa, h = 13 in of H₂O,

A sketch of the problem is uploaded along this answer.

Now

pA = patm + 13 in of H₂O ( h × density × g )

pA= 79 + (13 × 0.0254 × 9.8 × 1000/1000)

pA = 82.23596 kPa

the absolute static pressure in the gas cylinder is 82.23596 kPa

4 0
4 years ago
Propane is to be compressed from 0.4 MPa and 360 K to 4 MPa using a two-stage compressor. An interstage cooler returns the tempe
kow [346]

Answer:

a. 81 kj/kg

b. 420.625K

c.  101.24kj/kg

Explanation:

\frac{t2}{t1} =[\frac{p2}{p1} ]^{\frac{y-1}{y} }

t1 = 360

p1 = 0.4mpa

p2 = 1.20

y = 1.13

substitute these values into the equation

\frac{t2}{360} =[\frac{1.20}{0.4} ]^{\frac{1.13-1}{1.13} }

\frac{t2}{360} =[\frac{1.2}{0.4} ]^{0.1150}\\\frac{t2}{360} =1.1347

when we cross multiply

t2 = 360 * 1.1347

= 408.5

a. the work required in the firs compressor

w=c(t2-t1)

c=1.67x10³

t1 = 360

t2 = 408.5

w = 1670(408.5-360)

= 1670*48.5

= 80995 J

= 81KJ/kg

b. n=\frac{t2-t1}{t'2-t1}

n = 80%

t2 = 408.5

t1 = 360

0.80 = 408.5-360 ÷ t'2-360

0.80 =\frac{48.5}{t'2-360}

cross multiply to get the value of t'2

0.80(t'2-360) = 48.5

0.80t'2 - 288 = 48.5

0.8t'2 = 48.5+288

0.8t'2 = 336.5

t'2 = 336.5/0.8

= 420.625

this is the temperature at the exit of the first compressor

c. cooling requirement

w = c(t2-t1)

= 1.67x10³(420.625-360)

= 1670*60.625

= 101243.75

= 101.24kj/kg

8 0
3 years ago
If the reading of mercury manometer was 728 mmHg, what is the reading for another liquid such as water in mH20 units?​
vodka [1.7K]

Answer:

mH275 units

Explanation:

  • that was true
4 0
3 years ago
Trent is designing the grounds for a massive outdoor skate park. He has no experience with skateboarding at all, and although he
alexandr1967 [171]

Answer:

I’m sorry I don’t understand this is there more steps?‍♀️

Explanation:

8 0
3 years ago
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