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umka2103 [35]
3 years ago
11

If an atom of Magnesium (Mg) and an atom of Chlorine (Cl) bond to form Magnesium Chloride, what type of bond will they form?

Chemistry
2 answers:
Mariulka [41]3 years ago
5 0

Answer:

Ionic

Explanation:

This is because it is a metal and a non-metal and they form an ionic bond. Here, the formula is MgCl_2 because Mg loses 2 electrons Cl . on gains 1. So to balance the charges, there needs to be 2 Cl and 1 Mg.

Monica [59]3 years ago
4 0

Answer:

ionic bond

Explanation:

Covalent bonds are formed when two or more atoms share electrons between them. So two chlorine anions form an ionic bond with one magnesium cation for form MgCl2, a neutral chemical compound.

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Liono4ka [1.6K]

Answer:

d and e - Sodium and antimony

Explanation:

The atomic numbers remain the same, while the mass numbers change (because neutrons are being added or taken away).

sodium has an atomic number of 19 and a mass number of 39 - in d, it has an atomic number of 19 but a mass number of 40. therefore, it is an isotope

antimony has an atomic number of 51 and a mass number of 121.60 - in e, it has an atomic number of 51, but a mass number of 123. therefore, it is an isotope

6 0
3 years ago
Elements
Snezhnost [94]

Answer:

elements are composed of

electrons with a little mass and negative charge

protons with mass and positive charge

neutrons with mass and no charge

isotopes same number of protons, different in neutrons

share me the other part of the photo to complete!!!

7 0
3 years ago
Standard atmospheric pressure corresponds to the normal air pressure at sea level.
jekas [21]
Im not really sure what your asking.... <span>Standard sea-level pressure, by definition, equals 760 mm (29.92 inches) of mercury, </span>14.70 pounds per square inch<span>, 1,013.25 × 10 </span>3<span> dynes per square centimetre, 1,013.25 millibars, one standard atmosphere, or 101.325 kilopascals.

</span><span>""atmospheric pressure | Britannica.com""</span>
6 0
3 years ago
A dilute solution is prepared by transferring 40.00 ml of a 0.3433 m stock solution to a 750.0 ml volumetric flask and diluting
alina1380 [7]
We are given with the initial volume of the substance and the molarity. The first thing that needs to be done is to multiply the equation in order to obtain the number of moles such as shown below.
  
    number of moles = (40 mL) x (1 L / 1000 mL) x (0.3433 moles / L)
           number of moles = 0.013732 moles

To get the value of the molarity of the diluted solution, we divide the number of moles by the total volume.
          molarity = (0.013732 moles) / (750 mL / 1000 mL/L) = 0.0183 M

Similarly, we can solve for the molarity by using the equation,
           M₁V₁ = M₂V₂
Substituting the known values in the equation,
     (0.3433 M)(40 mL) = M₂(750 mL)
              M₂ = 0.0183 M
5 0
3 years ago
If a scientist has a 105 mL solution of 0.08 M HCl, then to a good approximation, what will be the pH of the solution? Enter you
djyliett [7]

Answer:

5667

Explanation:

6 0
2 years ago
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