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tangare [24]
2 years ago
7

The element chlorine has two stable isotopes, chlorine-35 with a mass of 34.97 amu and chlorine-37 with a mass of 36.95 amu. Fro

m the atomic weight of Cl = 35.45 one can conclude that:
Chemistry
1 answer:
sergejj [24]2 years ago
7 0

<u>Answer: </u>One isotope has a percentage abundance of 75.75 % and the percentage abundance of another isotope is 24.24%.

<u>Explanation:</u>

We are given the two stable isotopes of chlorine with their respective masses. The average atomic mass of chlorine is also given.

Average atomic mass of chlorine = 35.45 amu.

Let us assume the fractional abundance of one isotope be 'x' and the fractional abundance for another isotope will be (1 - x) because the total fractional abundance is always equal to 1.

  • For Chlorine-35 isotope:

Fractional abundance = x

Mass = 34.97 amu

  • For Chlorine-37 isotope:

Fractional abundance = 1 - x

Mass = 36.95 amu

The formula for the calculation of average atomic mass is given by:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

Putting values in above equation, we get:

35.45=34.97(x)+36.95(1-x)\\\\35.45=34.97x+36.95-36.95\\\\-1.5=-1.98x\\\\x=\frac{-1.5}{-1.98}=0.7575

1-x=1-0.7575=0.2424

Converting these two fractional abundances into percentage abundances by multiplying it with 100.

x=0.7575\times 100=75.75\%\\\\1-x=0.2424\times 100=24.24\%

Hence, one isotope has a percentage abundance of 75.75 % and the percentage abundance of another isotope is 24.24%.

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Is a solution a homogeneous or heterogeneous mixture
Alja [10]

Answer:

Solutions are always homogeneous.

Explanation:

Solution:

Solution are considered homogeneous because in solution the ratio of solute and solvent remain the same throughout the solution. Both solute and solvent are chemically combined and form a new substance.

In solution the particles of solute can not be seen through naked eye.

When the light is passed through the solution it can not scattered.

Example:

When salt is dissolve in water it makes a solution.

The solution also exist in gaseous form. For example oxygen and many other gases dissolved in nitrogen also form a solution.

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3 years ago
Q8. The titration of 15.00 mL of HBr solution of unknown concentration requires 18.44 mL of a 0.100 M KOH solution to reach the
lara [203]

Answer: 0.123 M

Explanation:

According to the neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HBr solution = ?

V_1 = volume of HBr solution = 15.00 ml

M_2 = molarity of KOH solution = 0.100 M

V_2 = volume of KOH solution = 18.44 ml

n_1 = valency of HBr = 1

n_2 = valency of KOH = 1

1\times M_1\times 15.00=1\times 0.100\times 18.44

M_1=0.123

Therefore, the concentration of the unknown HBr solution is 0.123 M

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