What kind of Sr3(PO4)2

For the reaction of C 2H 4( g) with O 2( g), to form CO 2( g) and H 2O( g), what number of grams of CO 2 could be produced from

maksim [4K]

Answer:

4.58g of CO₂ could be produced

Explanation:

Based on the reaction:

C₂H₄(g) + 3O₂(g) → 2CO₂(g) + 2H₂O(g)

1 mole of C₂H₄ reacts with 3 moles of oxygen to produce 2 moles of CO₂

To solve this question we must find the moles of each reactant in order to find limiting reactant. With limiting reactant we can find the moles -And the mass- of CO₂ produced:

Moles C₂H₄ -Molar mass: 28.05g/mol-

2.0g * (1mol / 28.05g) = 0.0713moles

Moles O₂ -Molar mass: 32g/mol-

5.0g * (1mol / 32g) = 0.156moles

For a complete reaction of 0.0713 moles of C2H4 are required:

0.0713 moles C₂H₄ * (3 moles O₂ / 1 mol C₂H₄) = 0.214 moles of O₂

As there are just 0.156 moles, O₂ is limiting reactant.

The moles of CO₂ produced are:

0.156 moles O₂ * (2mol CO₂ / 3mol O₂) = 0.104 moles CO₂

The mass is -Molar mass CO₂: 44.01g/mol-

0.104 moles CO₂ * (44.01g / mol) =

<h3>4.58g of CO₂ could be produced</h3>

4 0

3 years ago

Two states of matter are described below. State X: Particles are ions that are far apart State Y: Particles are molecules that a

Irina18 [472]

With the following choices:

State X = lightning; State Y = air.
State X = oxygen; State Y = neon.
State X = oxygen; State Y = ...

plz add other choices available. if there is no other choice, then

ans is State X = lightning; State Y = air

8 0

4 years ago

Read 2 more answers

Draw the structure corresponding to the followingname:_________.

natita [175]

Answer:

See figures 1 and 2

Explanation:

For this question, we can analyze each compound:

a. (4Z,3S)-2,4,7-trimethyl-3-amino-4-octene

In this case, we have to start with a carbon chain of 8 carbons. Then in carbons 2, 4 and, 7, we have to put three methyl groups ( $CH_3$ ). In carbon 4 we have to put an amino group ( $NH_2$ ). When we put the amino group in carbon 4 we will have a chiral carbon. So, we have to indicate the orientation in the bond of the amino group. If we want an "S" configuration the atoms must have a counterclockwise orientation. So, the amino group must have a dashed bond. Finally, in carbon 4 we have to put a double bond, the configuration of this double bond is "Z". So, the most important groups must be on the same side, in this case.

See figure 1 for further explanations

b. (3S,6R)-6-(2,4-dinitrophenyl)-3-amino-1-heptyne

In this case, we have to start with a chain of 7 carbons. In carbon 3 we have to put an amino group ( $NH_2$ ). When we put this group in carbons we will have a chiral carbon is the name we have an "S" configuration for this carbon. So, we have to use the dashed bond in order to have a counterclockwise orientation for all the atoms bonded on carbon 3. In carbon 6 we have to put a big group "2,4-dinitrophenyl". In this group, we have a bond with the main carbon chain in carbon 6 (of benzene), in this same benzene ring we have to put nitro groups ( $NH_2$ ) in carbons 2 and 4. Additionally, carbon 6 is a chiral carbon, and the configuration of this carbon is "R". Therefore we have to use a wedge bond for all the "2,4-dinitrophenyl" in order to have a clockwise orientation for all the atoms bonded on carbon 6. Finally, we have to put a triple bond between carbons 2 and 3.

See figure 2 to further explanations

7 0

3 years ago

What molecule is butane

Paladinen [302]

Butane is a gaseous molecule which is part of the organic compounds called hydrocarbon,

<h3>What kind of molecule is butane?</h3>

Butane is a gaseous molecule which is generally called a hydrocarbon.

Hydrocarbons are composed of only carbon and hydrogen. They are of organic origin.

Butane is a low molecular weight hydrocarbon which is used as a fuel.

In conclusion, butane is a gaseous hydrocarbon,

Learn more about hydrocarbons at: brainly.com/question/1489747

#SPJ1

5 0

2 years ago

Hi my name is Tytianna I´m 16 in a half years old

allochka39001 [22]

Answer:

whats up

Explanation:

7 0

3 years ago