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prisoha [69]
3 years ago
12

iodid ion is oxidized to hypoiodite ion by permanganate what is the ratio of hydroxide ions to iodide ions in balanced equation

Chemistry
1 answer:
ad-work [718]3 years ago
4 0

<u>Answer:</u> The ratio of number of hydroxide ions to iodide ions is 2 : 1.

<u>Explanation:</u>

The chemical equation for the oxidation of iodide ion is oxidized to hypoiodite ion by permanganate follows:

2MnO_4^-+I^-+H_2O\rightarrow 2MnO_2(s)+IO_3^{-}+2OH^{-}

According to mole concept:

1 mole of a substance contains 6.022\times 10^{23} number of particles

Moles of iodide ions = 1 mole

Number of iodide ions = (1\times 6.022\times 10^{23}

Moles of hydroxide ions = 2 mole

Number of hydroxide ions = (2\times 6.022\times 10^{23}

Taking the ratio of number of hydroxide ions and number of iodide ions are as follows:

\frac{\text{Number of hydroxide ions}}{\text{Number of iodide ions}}=\frac{(2\times 6.022\times 10^{23})}{(1\times 6.022\times 10^{23})}\\\\\frac{\text{Number of hydroxide ions}}{\text{Number of iodide ions}}=\frac{2}{1}

Hence, the ratio of number of hydroxide ions to iodide ions is 2 : 1.

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Based on the information provided in this question;

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Using P1/T1 = P2/T2

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