Question

iodid ion is oxidized to hypoiodite ion by permanganate what is the ratio of hydroxide ions to iodide ions in balanced equation

Answer 1

Answer: The ratio of number of hydroxide ions to iodide ions is 2 : 1.

Explanation:

The chemical equation for the oxidation of iodide ion is oxidized to hypoiodite ion by permanganate follows:

$2MnO_4^-+I^-+H_2O\rightarrow 2MnO_2(s)+IO_3^{-}+2OH^{-}$

According to mole concept:

1 mole of a substance contains $6.022\times 10^{23}$ number of particles

Moles of iodide ions = 1 mole

Number of iodide ions = $(1\times 6.022\times 10^{23}$

Moles of hydroxide ions = 2 mole

Number of hydroxide ions = $(2\times 6.022\times 10^{23}$

Taking the ratio of number of hydroxide ions and number of iodide ions are as follows:

$\frac{\text{Number of hydroxide ions}}{\text{Number of iodide ions}}=\frac{(2\times 6.022\times 10^{23})}{(1\times 6.022\times 10^{23})}\\\\\frac{\text{Number of hydroxide ions}}{\text{Number of iodide ions}}=\frac{2}{1}$

Hence, the ratio of number of hydroxide ions to iodide ions is 2 : 1.