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JulijaS [17]
3 years ago
14

Given f(x) = -3x + 21, find x when f(x) = 6.

Mathematics
1 answer:
Ainat [17]3 years ago
3 0

Answer:

x = 5

Step-by-step explanation:

Given

f(x) = - 3x + 21 and f(x) = 6, then equating gives

- 3x + 21 = 6 ( subtract 21 from both sides )

- 3x = - 15 ( divide both sides by - 3 )

x = 5

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20 + 0.10t

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Answer:

The picture is the answer.

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5 0
3 years ago
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Given the Arithmetic sequence A1,A2,A3,A4A1,A2,A3,A4
Bad White [126]
The given sequence is
a₁ = 29
a₂ = 39
a₃ = 49
a₄ = 59

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The n-th term is
a_{n}=a_{1}+(n-1)d
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7 0
2 years ago
What does 3 (2x - 4) = 8x 14 equal?
jeka57 [31]
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5 0
3 years ago
Given that tan^2 theta=3/8,what is the value of sec theta?
algol [13]

Answer:

The value of SecФ is  \pm \sqrt{\frac{11}{8}} .

Step-by-step explanation:

Given as for trigonometric function :

tan²Ф = \frac{3}{8}

Or, tanФ = \sqrt{\frac{3}{8} }

∵ tanФ = \frac{Perpendicular}{Base}

So,  \frac{Perpendicular}{Base} =  \sqrt{\frac{3}{8} }

So, Hypotenuse² = perpendicular² + base²

or, Hypotenuse² = ( \sqrt{3} )² + ( \sqrt{8} )²

Or,  Hypotenuse² = 3 + 8 = 11

Or,  Hypotenuse = ( \sqrt{11} )

Now SecФ = \frac{Hypotenuse}{Base}

or, SecФ = \frac{\sqrt{11}}{\sqrt{8}} = \sqrt{\frac{11}{8} }

<u>Second Method</u>

Sec²Ф - tan²Ф = 1

Or, Sec²Ф = 1 +  tan²Ф

or, Sec²Ф = 1 +  \frac{3}{8}

Or, Sec²Ф = \frac{11}{8}

Or,  SecФ = \pm \sqrt{\frac{11}{8}}

Hence The value of SecФ is  \pm \sqrt{\frac{11}{8}} . Answer

7 0
3 years ago
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