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JulijaS [17]
3 years ago
14

Given f(x) = -3x + 21, find x when f(x) = 6.

Mathematics
1 answer:
Ainat [17]3 years ago
3 0

Answer:

x = 5

Step-by-step explanation:

Given

f(x) = - 3x + 21 and f(x) = 6, then equating gives

- 3x + 21 = 6 ( subtract 21 from both sides )

- 3x = - 15 ( divide both sides by - 3 )

x = 5

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Vikki [24]

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If they never cross/ intersect each other

Step-by-step explanation:

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3 years ago
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Answer the question above on the ixl tab, please.
kramer

Answer:

<h2>The answer is 10</h2>

Step-by-step explanation:

The formula for finding the combination of two given positive numbers is given by

<h3>_{n}C _{r} =  \frac{n!}{(n - r)!r!}</h3>

Where n and r are positive numbers

From the question we have

5 C 3

<u>Simplify</u>

That's

<h3>\binom{5}{3}  =  \frac{5!}{(5 - 3)!3!}  =  \frac{120}{2! \times 3  !}  \\  =  \frac{120}{2 \times 6}  \\  =  \frac{120}{12}</h3>

We have the final answer as

<h3>10</h3>

Hope this helps you

8 0
3 years ago
6x – 3y = -33<br> - 6x + 5y = 31
Readme [11.4K]

Answer:

check online for more information

4 0
2 years ago
HELP ASAP WILL GIVE BRAINLYIST AND 30 POINTS
Ilia_Sergeevich [38]

Answer:

Angles A and E

Step-by-step explanation:

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6 0
3 years ago
Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.
liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

f(x) = \frac{x^2+4x+3}{x^2-x-2}

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial x^2-x-2

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

(x-2) (x + 1)

We do the same with the numerator

x^2+4x+3

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

(x+3)(x + 1)

Therefore

f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}

Note that \frac{(x+1)}{(x+1)}=1 only if x \neq -1

So since x = -1 is not included in the domain the function has a discontinuity in x = -1

3 0
3 years ago
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