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bogdanovich [222]

3 years ago

6

Graph the inequality -n_<-5

1 answer:

katrin [286]3 years ago

5 0

Answer:

See below

Step-by-step explanation:

This is just the same as n≤5, which would look like the attached number line.

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The perimeter of a square is increasing at a rate of 555 meters per hour. At a certain instant, the perimeter is 303030 meters.

BigorU [14]

Answer: $21,022,706.3\ m^2/hr$

Step-by-step explanation:

Given

The rate of change of perimeter of a square is increasing at a rate of $555\ m^3/hr$

At a certain instant, the perimeter is $303030\ m$

At this instant side of square is

$\Rightarrow a=\dfrac{303030}{4}\\\\\Rightarrow a=75,757.5\ m$

Rate of change of perimeter is

$\Rightarrow \dfrac{dp}{dt}=4\dfrac{da}{dt}\\\\\Rightarrow 555=4\dfrac{da}{dt}\\\\\Rightarrow \dfrac{da}{dt}=138.75\ m/hr$

At this instant, rate of change of the area of the square is

$\Rightarrow A=a^2\\\Rightarrow \dfrac{dA}{dt}=2a\dfrac{da}{dt}\\\\\Rightarrow \dfrac{dA}{dt}=2\times 75757.5\times 138.75\\\\\Rightarrow \dfrac{dA}{dt}=21,022,706.3\ m^2/hr$

8 0

3 years ago

Just answer 15 I need help on math

Olegator [25]

15.3 would be the answer

8 0

3 years ago

Read 2 more answers

Solve using substitution method: <br> X= y/3 +2 <br> 7x − 5y = 10<br><br> Solve for (x,y)

s344n2d4d5 [400]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:x = 5/2$

$\qquad \tt \rightarrow \: y = 3/2$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: x = \cfrac{y}{3} + 2 \: \: \: \: \: \: \: \: - (1)$

$\qquad \tt \rightarrow \: 7x -5 y = 10 \: \: - (2)$

$\textsf{put value of x in equation 2}$

$\qquad \tt \rightarrow \: 7 \bigg( \cfrac{y}{3} + 2 \bigg) - 5y = 10$

$\qquad \tt \rightarrow \: \cfrac{7y}{3} + 14 - 5y = 10$

$\qquad \tt \rightarrow \: \cfrac{7y}{3} - 5y = 10 - 14$

$\qquad \tt \rightarrow \: \cfrac{7y - 15y}{3} = - 4$

$\qquad \tt \rightarrow \: - 8y = - 4(3)$

$\qquad \tt \rightarrow \: y = \cfrac{ - 12}{ - 8}$

$\qquad \tt \rightarrow \: y = \cfrac{ 3}{ 2}$

$\textsf{put value of y in equation 1 }$

$\qquad \tt \rightarrow \: x = \cfrac{y}{3} + 2$

$\qquad \tt \rightarrow \: x = \bigg (\cfrac{3}{2} \sdot\cfrac{1}{3} \bigg) + 2$

$\qquad \tt \rightarrow \: x = \cfrac{1}{2} + 2$

$\qquad \tt \rightarrow \: x = \cfrac{1 + 4}{2}$

$\qquad \tt \rightarrow \: x = \cfrac{5}{2}$

4 0

2 years ago

ABCD is a rectangle.

grandymaker [24]

Answer:

i need more details

Step-by-step explanation:

8 0

3 years ago

Evaluate (2 - 3)4(4) - 9 ÷ 3. -7 -2 1 2

insens350 [35]

Answer:

your answer is -8

4 0

3 years ago

Read 2 more answers