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bogdanovich [222]
3 years ago
6

Graph the inequality -n_<-5

Mathematics
1 answer:
katrin [286]3 years ago
5 0

Answer:

See below

Step-by-step explanation:

This is just the same as n≤5, which would look like the attached number line.

You might be interested in
Divide 16x3 – 12x2 + 20x – 3 by 4x + 5.
nalin [4]

Answer:

4x^2 - 8x + 15 - \frac{78}{4x+5}

Step-by-step explanation:

<em>To solve polynomial long division problems like these, it's helpful to build a long division table. Getting used to building these can make problems like this much simpler to solve.</em>

Begin by looking at the first term of the cubic polynomial.

What would we have to multiply 4x + 5 by to get an expression containing 16x^3? The answer is 4x^2, since (4x + 5) \times 4x^2 = 16x^2 + 20x.

This is the first step of our long division, and we write out the start of our long division table like this:

{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,4x^2\\4x + 5\quad)\!\!\overline{\,\,\,16x^3 - 12x^2 + 20x - 3}\\{ }\qquad{ }\quad{ }\quad{ }\,\,16x^3 + 20x^2\\

On the left is the divisor. On top is 4x^2. In the middle is the polynomial we are dividing, and on the bottom is the result of multiplying our divisor by

The next step is to subtract the bottom expression from the middle one, like so:

{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,4x^2\\4x + 5\quad)\!\!\overline{\,\,\,16x^3 - 12x^2 + 20x - 3}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\underline{16x^3 + 20x^2}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,0x^3 - 32x^2\\

We are left with -32x^2. The next thing to do is to add the next term of the polynomial we are dividing to the bottom line, like this:

{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,4x^2\\4x + 5\quad)\!\!\overline{\,\,\,16x^3 - 12x^2 + 20x - 3}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\underline{16x^3 + 20x^2}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,\,\,\,\,\,\,\,\,\, - 32x^2 + 20x\\

Now we return to the beginning of the instructions, and repeat the process: namely, what would we have to multiply 4x + 5 by to get an expression containing -32x^2? The answer is -8x, and we fill out our long division table like so:

{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,4x^2 - \,\,\,\,8x\\4x + 5\quad)\!\!\overline{\,\,\,16x^3 - 12x^2 + 20x - 3}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\underline{16x^3 + 20x^2}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,\,\,\,\,\,\,\,\,\, - 32x^2 + 20x\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,\,\,\,\,\,\,\,\,\, - 32x^2 - 40x\\

Once again, we subtract the bottom expression from the one above it, and include the next term of the divisor, like so:

{ }\qquad{ }\qquad{ }\quad{ }4x^2 - \,\,\,\,8x \,+ 15\\4x + 5\quad)\!\!\overline{\,\,\,16x^3 - 12x^2 + 20x - 3}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\underline{16x^3 + 20x^2}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,\,\,\,\,\,\,\,\,\, - 32x^2 + 20x\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\underline{- 32x^2 - 40x}\\{ }\qquad{ }\qquad{ }\qquad{ }\qquad{ }\qquad{ }\,\,\,\,\,60x - 3\\

And repeat. What do we multiply 4x + 5 by to get an expression containing 60x? The answer is 15. Our completed long division table looks like this:{ }\qquad{ }\qquad{ }\quad{ }4x^2 - \,\,\,\,8x \,+15\\4x + 5\quad)\!\!\overline{\,\,\,16x^3 - 12x^2 + 20x - 3}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\underline{16x^3 + 20x^2}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,\,\,\,\,\,\,\,\,\, - 32x^2 + 20x\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\underline{- 32x^2 - 40x}\\{ }\qquad{ }\qquad{ }\qquad{ }\qquad{ }\qquad{ }\,\,\,\,\,60x - 3\\{ }\qquad{ }\hspace{3cm}\,\,\underline{60x + 75}\\{ }\hspace{4.3cm}\,\,-78

Now, the expression at the top,

4x^2 - 8x + 20x + 15

is our quotient, and the last number, -78, is our remainder.

Hence we arrive at the solution of

\frac{16x^3-12x^2+20x-3}{4x+5} =4x^2 - 8x + 15 - \frac{78}{4x+5}.

6 0
3 years ago
if 7 is added to twice a number and this sum is multiplied by 2, the result the same as if the number is multiplied by -8 and 2
Nady [450]
X - the number

2(2x+7)=-8x+2 \\&#10;4x+14=-8x+2 \\&#10;4x+8x=2-14 \\&#10;12x=-12 \\&#10;x=\frac{-12}{12} \\&#10;x=-1

The number is -1.
7 0
3 years ago
Solve for q: 2w =A/q
Anastasy [175]

Answer:

q = A/2w

Please give me brainliest! Sorry if it's wrong.

6 0
3 years ago
Find the area of a parallelogram with a base of 10cm and height of 5cm. Write the area first and show your work.
STatiana [176]

Answer:

50 cm^{2}

Step-by-step explanation:

The equation to finding the area of a parallelogram is base*height.

Plugging in those numbers gives us 10 cm*5 cm.

That is 50cm^{2}.

5 0
3 years ago
Time magazine reported the result of a telephone poll of 800 adult Americans. The question posed of the Americans who were surve
Elden [556K]

The observed value of z (test statistic) is greater than 1.96 (the test statistic does fall into the rejection region), so Reject H₀ .

p₁ = the proportion of the non-smoker population who reply "yes"

p₂ = the proportion of the smoker population who reply "yes," then we are interested in testing the null hypothesis

H₀:  p₁ = p₂

Alternate hypothesis:

Hₐ:  p₁≠p₂

That implies then that the test statistic for testing:

H₀ : p1 = p2

Hₐ : p1 ≠ p2.                              (Two – tailed)

n1 = 605, y1 = 351

p1 = y1 / n1

= 351/605

≈ 0.58

n2 = 195, y2 = 41.

p2 = y2/n2

= 41 / 195

≈0.21

p = y1 + y2 / n1 + n2

= 351 + 41 / 605 + 195

= 392 / 800

= 0.49

The test statistic is

z = \frac{p1 - p2}{\sqrt{p(1-p). (\frac{1}{n1}}+ \frac{1}{n2} ) } }

z = \frac{0.58 - 0.21}\sqrt{{0.49 . 0.51 (\frac{1}{605} + \frac{1}{195}  )} }    

= 8.988

critical region for α = 0.01

z = 2.576

The observed value of z (test statistic) is greater than 1.96 (the test statistic does fall into the rejection region),

so Reject H₀ .

To learn more about hypothesis testing from the given link

brainly.com/question/4232174

#SPJ4

7 0
2 years ago
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