1 mole of any particles = 6.02* 10²³ particles
4.5*10²⁵ atoms Ni* 1 mol Ni/6.02*10²³ Ni ≈ 74.75≈ 75 mol Ni
Basically the theory centers on the idea that an atom of iron dumped into the sea results in the conversion of 10,000 molecules of carbon dioxide to carbohydrates. John Martin's hypothesis is that the growth of phytoplankton is limited by the amount of iron dissolved in sea water. Lab experiments done by him then showed that indeed, adding a small amount of iron accelerated the growth of plankton.
Answer: The correct answer is D.
Explanation:
As you can see in every step of the pathway, ATP is not generated directly. Although, in the oxidative phase, molecules of NADPH are produced and these can be used for synthesize ATP indirectly; the NADPH molecules are hihgly demanded in tissues that carry out constantly synthesis of fatty acids, such as liver.
Therefore the correct answer is D.
Answer:
When halogen elements react with group one metals they form halide salts.
Explanation:
The elements of group 17 are called halogens. These are six elements Fluorine, Chlorine, Bromine, Iodine, Astatine. Halogens are very reactive these elements can not be found free in nature. Their chemical properties are resemble greatly with each other. As we move down the group in periodic table size of halogens increases that's way fluorine is smaller in size as compared to other halogens elements. Their boiling points also increases down the group which changes their physical states. i.e fluorine is gas while iodine is solid.
When halogen elements react with group one metals they form halide salts.
Alkali metals have one valance electron and halogens needed one electron to complete the octet thus alkali metals loses one electron which is accepted by halogens atom and form ionic compound called halide salts.
For example:
2Na + Cl₂ → 2NaCl
2K + Cl₂ → 2KCl
2Rb + Cl₂ → 2RbCl
2Li + Cl₂ → 2LiCl
With bromine:
2Na + Br₂ → 2NaBr
2K + Br₂ → 2KBr
2Rb + Br₂ → 2RbBr
2Li + Br₂ → 2LiBr
With iodine:
2Na + I₂ → 2NaI
2K + I₂ → 2KBI
2Rb + I₂ → 2RbI
2Li + I₂ → 2LiI
The correct answer is BI₃
Lewis acid refers to a compound that could accept a pair of electrons, while Lewis base refers to a compound that could donate a pair of electrons.
In the mentioned reaction,
In NH₃, nitrogen exhibits a lone pair of electrons and is functioning as a Lewis base. In BI₃, the boron is deficient for an electron pair, thus in order to complete its octet it functions as a Lewis acid.
