What is the value of ΔG in a spontaneous reaction?

Chemistry

2 answers:

Amanda [17]3 years ago

7 0

The value of Triangle G is A) Less than 0.

Verdich [7]3 years ago

3 0

Answer: A.) Less than 0

Explanation: Spontaneous Reactions are the reaction in which the reaction moves more towards the product side.

It is the reaction in which there is a release of free energy and the the reaction will move towards the stable energy state.

Thus the ΔG for a spontaneous reaction must always be less than zero and E must always be greater than zero.

ΔG = change in gibbs free energy and E = electrochemical potential.

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A sodium ion, Na+, with a charge of 1.6×10−19C and a chloride ion, Cl− , with charge of −1.6×10−19C, are separated by a distance

sasho [114]

Answer:

$W\geq 2.1x10^{-19}J$

Explanation:

Due to Coulomb´s law electric force can be described by the formula $F=K\frac{q_{1}.q_{2}}{r^{2}}$ , where K is the Coulomb´s constant ( $9x10^{9} N\frac{m^{2} }{C^{2} }$ ), $q_{1}$ = Charge 1 (Na+ in this case), $q_{2}$ is the charge 2 (Cl-) and r is the distance between both charges.

Work made by a force is W=F.d and total work produced is the change in energy between final and initial state. this is $W=W_{f} -W_{i}$ .

so we have $W=W_{f} -W_{i} =(K\frac{q_{(Na+)}q_{(Cl-)}rf}{r_{f} ^{2}})-(K\frac{q_{(Na+)}q_{(Cl-)}ri}{r_{i} ^{2}})=Kq_{(Na+)}q_{(Cl-)[\frac{1}{{r_{f}}} -\frac{1}{{r_{i}}}]$